Python 什么'；我的def函数有什么问题？如何修复它？

数据如下： [('1985-08', '15.00'), ('1985-08', '14.88'), ('1985-08', '15.25'), ('1985-08', '15.25'), ('1985-08', '15.13'), ('1985-08', '14.75'), ('1985-08', '14.88'), ('1985-08', '15.25'), ('1985-08', '15.25'), ('1985-08', '15.00'), ('1985-08', '14.63'), ('1985-08', '14.50'), ('1985-08', '14.63'), ('1985-08', '15.25'), ('1985-08', '15.00'), ('1985-08', '15.25'), ('1985-08', '15.13'), ('1985-08', '14.88'), ('1985-08', '15.25'), ('1985-08', '15.38'), ('1985-08', '15.75'), ('1985-08', '15.88'), ('1985-07', '15.88'), ('1985-07', '16.25'), ('1985-07', '16.00'), ('1985-07', '16.62'), ('1985-07', '16.62'), ('1985-07', '16.25'), ('1985-07', '16.50'), ('1985-07', '16.87'), ('1985-07', '17.37')，（'1985-07'，'17.25'），（'1985-07'，'17.62'），（'1985-07'，'17.50'），（'1985-07'，'17.75'），（'1985-07'，'17.87'），（'1985-07'，'18.00'），（'1985-07'，'18.00'），（'1985-07'，'17.62'），（'1985-07'，'17.62'），（'1985-07'，'17.50'），（'1985-07'，'17.25'），（'1985-07'，'18.12'）]

我的代码：

def average_data(list_of_tuples):
strMonth = []
counter = 0
addition = 0
while True:
    if (strMonth[counter])[0] == (strMonth[counter+1])[0]:    #line 31
        addition += float(strMonth[counter][1])
        result2 = addition
    else:
        continue
print(result2)
return result2
def main(): 
    file_obj = get_input_descriptor()
    column = int(input('What column:'))
    get_data_list(file_obj, column)
    result2 =get_data_list(file_obj, column)

average_data(result2)
file_obj.close()
main()

Python Shell的错误代码：

  File "C:\Users\admin\Desktop\proj.py", line 31, in average_data
if (strMonth[counter])[0] == (strMonth[counter+1])[0]:
IndexError: list index out of range

---

有什么问题吗？我想得到每个月的数字之和。有没有其他方法来解决这个问题？

strMonth

是空的。它没有第0个元素，所以

strMonth[计数器]

会引发一个

索引器

：

In [29]: strMonth = []

In [30]: counter = 0

In [31]: strMonth[counter]
IndexError: list index out of range

---

您可以使用

dict

（或a）将yearmonth字符串映射到表示值之和的浮点

import collections
def average_data(strMonth):
    result = collections.defaultdict(float)
    for yearmonth, val in strMonth:
        result[yearmonth] += float(val)
    return dict(result)

def main(): 
    result2 = [('1985-08', '15.00'), ('1985-08', '14.88'), ('1985-08', '15.25'), ('1985-08', '15.25'), ('1985-08', '15.13'), ('1985-08', '14.75'), ('1985-08', '14.88'), ('1985-08', '15.25'), ('1985-08', '15.25'), ('1985-08', '15.00'), ('1985-08', '14.63'), ('1985-08', '14.50'), ('1985-08', '14.63'), ('1985-08', '15.25'), ('1985-08', '15.00'), ('1985-08', '15.25'), ('1985-08', '15.13'), ('1985-08', '14.88'), ('1985-08', '15.25'), ('1985-08', '15.38'), ('1985-08', '15.75'), ('1985-08', '15.88'), ('1985-07', '15.88'), ('1985-07', '16.25'), ('1985-07', '16.00'), ('1985-07', '16.62'), ('1985-07', '16.62'), ('1985-07', '16.25'), ('1985-07', '16.50'), ('1985-07', '16.87'), ('1985-07', '17.37'), ('1985-07', '17.25'), ('1985-07', '17.62'), ('1985-07', '17.50'), ('1985-07', '17.75'), ('1985-07', '17.87'), ('1985-07', '18.00'), ('1985-07', '18.00'), ('1985-07', '17.62'), ('1985-07', '17.62'), ('1985-07', '17.62'), ('1985-07', '17.50'), ('1985-07', '17.25'), ('1985-07', '18.12')]
    print(average_data(result2))
main()

屈服

{'1985-07': 378.08000000000004, '1985-08': 332.16999999999996}

python 3.2

  M=List_of_tuples

  sum(int(m.split("-")[1]) for m,t in M)

---

你应该解释你想做什么，这会有帮助的。