Python 烧瓶：错误的请求POST 400

我用烧瓶和火炉。我在satis.html中有2个按钮。当用户按下按钮2时，我想从数据库中检索一些数据并显示出来。但我得到了“坏请求”错误

这是我的密码：

@app.route('/satis', methods=['GET', 'POST'])
def satis():
    if (request.method == 'POST'):
                sehir=request.form['il']
                yas=request.form['yas']
                id=request.form['id']
                gun=request.form['satisgunu']
                cins=request.form['cinsiyet']
                tarz=request.form['satistarzi']
                db = firebase.database()
                db.child("names").push({"sehir": sehir,"yas":yas,"id":id,"gun":gun,"cins":cins,"tarz":tarz})
                todo = db.child("names").get()
                to = todo.val()
                if request.form['submit'] == 'add':
                    db = firebase.database()
                    users_by_score = db.child("names").order_by_child("id").equal_to("2").get()
                    us = users_by_score.val()
                    return render_template('satis.html', t=to.values(),u=us.values())
                return render_template('satis.html', t=to.values())

---

您只处理了for post方法。您还需要处理GET方法的情况

@app.route('/satis', methods=['GET', 'POST'])
def satis():
    db = firebase.database()
    todo = db.child("names").get()
    to = todo.val()
    if (request.method == 'POST'):
                sehir=request.form['il']
                yas=request.form['yas']
                id=request.form['id']
                gun=request.form['satisgunu']
                cins=request.form['cinsiyet']
                tarz=request.form['satistarzi']
                db.child("names").push({"sehir": sehir,"yas":yas,"id":id,"gun":gun,"cins":cins,"tarz":tarz})
                if request.form['submit'] == 'add':
                    db = firebase.database()
                    users_by_score = db.child("names").order_by_child("id").equal_to("2").get()
                    us = users_by_score.val()
                    return render_template('satis.html', t=to.values(),u=us.values())
    return render_template('satis.html', t=to.values())

---

如果（request.method=='POST'），请删除此项，并在URL中传递数据。发出get请求并查看发生了什么。您将收到错误消息。请始终将完整的错误消息（从单词“Traceback”开始）作为文本（而不是屏幕截图）放入问题中（不是coment）。还有其他有用的信息。