从google表单python BeautifulSoup获取字段ID

例如，在谷歌表单中：如何创建此“字段ID”的列表

var FB_PUBLIC_LOAD_DATA_ = [null,[null,[[831400739,"Product Title",null,0,[[1089277187,null,0]
]
]
,[2054606931,"SKU",null,0,[[742914399,null,0]
]
]
,[1620039602,"Size",null,0,[[2011436433,null,0]
]
]
,[445859665,"First Name",null,0,[[638818998,null,0]
]
]
,[1417046530,"Last Name",null,0,[[1952962866,null,0]
]
]
,[903472958,"E-mail",null,0,[[916445513,null,0]
]
]
,[549969484,"Phone Number",null,0,[[848461347,null,0

这是HTML的相关部分^

到目前为止，我已经掌握了代码：

    from bs4 import BeautifulSoup as bs
    a = requests.get(url, proxies=proxies)
    soup = bs(a.text, 'html.parser')
    fields = soup.find_all('script', {'type': 'text/javascript'})
    form_info = fields[1]
    print(form_info)

但这会返回大量不相关的数据，除非我包含大量的

str.replace（）

，

str.split（）

代码部分，否则我看不到一个简单的方法来实现这一点。这也会非常混乱

我不必使用BeautifulSoup，尽管这似乎是显而易见的方法

在上面的示例中，我需要一个如下列表：

---

[1089277187742914399201143638818998195296286616445513 84848461347]

Beautiful soup用于查询HTML标记。因此，从JavaScript变量提取数据的方法是使用regex。您可以在

[[

上进行匹配。但是，这将返回

831400739

。可以通过跳过第一项在正则表达式之后手动排除此项

import re

script = '''var FB_PUBLIC_LOAD_DATA_ = [null,[null,[[831400739,"Product Title",null,0,[[1089277187,null,0]
]
]
,[2054606931,"SKU",null,0,[[742914399,null,0]
]
]
,[1620039602,"Size",null,0,[[2011436433,null,0]
]
]
,[445859665,"First Name",null,0,[[638818998,null,0]
]
]
,[1417046530,"Last Name",null,0,[[1952962866,null,0]
]
]
,[903472958,"E-mail",null,0,[[916445513,null,0]
]
]
,[549969484,"Phone Number",null,0,[[848461347,null,0'''

match = re.findall('(?<=\[\[)(\d+)', script) 
# (?<= ) means to look for the following (but not include it in the results):
# \[\[ means find 2 square brackets characters. The backslash is used to tell regex to use the character [ and not the function.
# (\d+) means to match the start of a digit of any size (and return it in results)

results = [x for x in match[1:]] # Skip the first item, which is 831400739
print(results)

您可能希望将结果强制转换为整数。此外，为了使代码更加健壮，您可能希望在调用正则表达式函数之前删除空格和新行，例如：

formatted=script.replace（“，”）.replace（“\n'，”）.replace（“\r'，”）

['1089277187', '742914399', '2011436433', '638818998', '1952962866', '916445513', '848461347']