Python中的电梯模拟器

我需要Python中的电梯模拟器的帮助，但我没有太多经验。应该有用户输入的具有随机起始楼层和目标楼层的客户数量。现在我正在编写一个简单的策略，电梯一路往上，然后再回到底部。当我运行代码时，程序会无限循环。我不明白为什么。此外，我不知道如何对我的建筑的输出方法进行编码，我想显示哪些客户有哪些楼层，电梯访问了多少楼层。谢谢你的帮助

import random

class Elevator(object):
    def __init__(self, num_of_floors, register_list, direction = "up", cur_floor=1):
        self.total_floors = num_of_floors
        self.reg_list = register_list
        self.floor = cur_floor
        self.direct = direction
    def move(self):
        """Moves the elevator one floor"""
        if self.total_floors == self.floor:
            self.direct = "down"
        if self.direct == "up":
            self.floor += 1
        else:
            self.floor -= 1
    def register_customer(self, customer):
        self.reg_list.append(customer)
    def cancel_customer(self, customer):
        self.reg_list.remove(customer)

class Building(object):
    def __init__(self, num_of_floors, customer_list, elevator):
        self.total_floors = num_of_floors
        self.customers = customer_list
    def run(self):
        while elevator.floor != 0:
            for customer in self.customers:
                if elevator.floor == customer.on_floor:
                    elevator.reg_list.append(customer)
                    customer.indicator = 1
                elif elevator.floor == customer.going_floor:
                    elevator.reg_list.remove(customer)
                    customer.indicator = 0
                    customer.fin = 1
            elevator.move()
                
    def output(self):
        pass

class Customer(object):
    def __init__(self, ID, num_of_floors, cur_floor=0, dst_floor=0, in_elevator=0, finished=0):
        self.ident = ID
        self.indicator = in_elevator
        self.fin = finished
        cur_floor = random.randint(1, num_of_floors)
        self.on_floor = cur_floor
        dst_floor = random.randint(1, num_of_floors)
        while dst_floor == cur_floor:
            dst_floor = random.randint(1, num_of_floors)
        self.going_floor = dst_floor
    

customer_count = int(input("How many customers are in the building?: "))
floor_count = int(input("How many floors does the building have?: "))
cus_list = []
for i in range(1, customer_count+1):
    cus_list.append(Customer(i, floor_count))
elevator = Elevator(floor_count, cus_list)
building = Building(floor_count, cus_list, elevator)

---

你的问题在于：

def run(self):
    while elevator.floor != 0:
        print(elevator.floor)
        for customer in self.customers:
            print(customer)
            if elevator.floor == customer.on_floor:
                elevator.reg_list.append(customer)
                customer.indicator = 1
            elif elevator.floor == customer.going_floor:
                elevator.reg_list.remove(customer)
                customer.indicator = 0
                customer.fin = 1
        elevator.move()

当您执行电梯.reg_list.append（客户）时，您将客户重新追加到列表中，并增加其大小（self.customers也是对该列表的引用），因此“self.customers中的for customer”将永远循环

下面是“客户列表”：

电梯是在FYI类范围之外创建的全局变量

修复可能如下所示

电梯一开始是空的，对吗

class Elevator(object):
    def __init__(self, num_of_floors, register_list, direction = "up", cur_floor=1):
        self.total_floors = num_of_floors
        self.reg_list = []

---

我不想坐电梯：P检查一下你在大楼里的while环，看起来很有趣。。。尝试将电梯.floor变量输出到循环中的控制台。这

而
循环对我来说很好-它表示客户将要去他/她所在楼层以外的楼层。很抱歉，编辑了该变量。只要楼层数足够大；）不，它们是对同一列表的两个不同引用。OP可能应该在电梯中使用
self.reg\u list=[]
，这样电梯就不会完全启动。是的，我在上面的回答中提到了相同的列表。抱歉，时间太长了：我会继续展示电梯的功能吗？例如，使用打印语句显示“电梯在一楼接客户1……电梯移到二楼接客户3……电梯移到三楼，放下客户1，接客户4……等等”。例如：打印（“电梯接客户”+客户+“在楼层”+电梯.楼层）这是python 3语法。Python 2省略了“（”s
 elevator.reg_list.append(customer)

class Elevator(object):
    def __init__(self, num_of_floors, register_list, direction = "up", cur_floor=1):
        self.total_floors = num_of_floors
        self.reg_list = []