我的任务是用逗号分隔的随机数创建一个文件。编写python代码来求和并平均它们。如何做到这一点？

此代码在运行时显示错误：AttributeError:“tuple”对象没有属性“write”

可用于生成随机数：

n = ("random_numbers", "r+")
a = int(input("How many number do want to input? Type 0 to exit:"))

sum = 0
count = 0
number = 0

for i in range(a):
    x = int(input("Enter a number:"))
    n.write(str(x) + str(','))
    sum = sum + number
    count += 1

average = sum/count

n.write('the sum of the numbers is' + sum)
n.write('the average of the numbers is' + average)
n.seek(0)
n.read()
n.close()

在上面的示例中，如果您有

a

>1000，则此代码不起作用，另一种生成随机数的方法是：

import random

a = int(input("How many number do want to input?"))

with open('my_file.txt', 'w') as fp:
    my_numbers = random.sample(range(1000), a)
    fp.write(','.join(map(str, my_numbers)))
    fp.write( '\nthe sum of the numbers is ' + str(sum(my_numbers)))
    fp.write( '\nthe average of the numbers is ' + str(sum(my_numbers) / len(my_numbers)))

使用

您可以使用生成随机数：

n = ("random_numbers", "r+")
a = int(input("How many number do want to input? Type 0 to exit:"))

sum = 0
count = 0
number = 0

for i in range(a):
    x = int(input("Enter a number:"))
    n.write(str(x) + str(','))
    sum = sum + number
    count += 1

average = sum/count

n.write('the sum of the numbers is' + sum)
n.write('the average of the numbers is' + average)
n.seek(0)
n.read()
n.close()

在上面的示例中，如果您有

a

>1000，则此代码不起作用，另一种生成随机数的方法是：

import random

a = int(input("How many number do want to input?"))

with open('my_file.txt', 'w') as fp:
    my_numbers = random.sample(range(1000), a)
    fp.write(','.join(map(str, my_numbers)))
    fp.write( '\nthe sum of the numbers is ' + str(sum(my_numbers)))
    fp.write( '\nthe average of the numbers is ' + str(sum(my_numbers) / len(my_numbers)))

---

必须使用

打开文件才能写入。仅仅声明要打开的参数会创建一个参数元组，它不会调用open函数。n=打开（“随机数”，“w”）必须打开一个文件才能写入。仅仅声明要打开的参数会创建一个参数元组，它不会调用open函数。n=开放（“随机数”，“w”）