Python 从元组列表创建格式化表
我有一个如下所示的数据列表:Python 从元组列表创建格式化表,python,python-2.7,formatting,format,Python,Python 2.7,Formatting,Format,我有一个如下所示的数据列表: [ ( 1, u'python -c \'print("ok")\'', u'data', u'python' ), ( 2, u'python -c \'print("this is some data")\'', u'data', u'python' ) ] Language | Type | Pay
[
(
1,
u'python -c \'print("ok")\'',
u'data',
u'python'
), (
2,
u'python -c \'print("this is some data")\'',
u'data',
u'python'
)
]
Language | Type | Payload
-------------------------------
python | data | python -c 'print("ok")'
python | data | python -c 'print("this is some data")'
这些数据从数据库中取出并以此显示,并且不断增长。我想做的是像这样显示数据:
[
(
1,
u'python -c \'print("ok")\'',
u'data',
u'python'
), (
2,
u'python -c \'print("this is some data")\'',
u'data',
u'python'
)
]
Language | Type | Payload
-------------------------------
python | data | python -c 'print("ok")'
python | data | python -c 'print("this is some data")'
我有一个函数可以做同样的事情,但它并不完全符合预期:
def print_table(data, cols, width):
n, r = divmod(len(data), cols)
pattern = "{{:{}}}".format(width)
line = "\n".join(pattern * cols for _ in range(n))
last_line = pattern * r
print(line.format(*data))
print(last_line.format(*data[n*cols]))
如何使数据的输出看起来像所需的那样?从答案来看,可以使用熊猫,但我还想知道一种不安装外部模块的方法您可以使用熊猫:
import pandas as pd
data = pd.DataFrame(a, columns=['id','Payload', 'type', 'Language'])
print(data)
给你:
id Payload type Language
0 1 python -c 'print("ok")' data python
1 2 python -c 'print("this is some data")' data python
分析数据的最大宽度,并使用字符串格式-稍后使用一些“创造性”格式:
data = [
(
1,
u'python -c \'print("ok")\'',
u'data',
u'python'
), (
2,
u'python -c \'print("this is some data")\'',
u'data',
u'python'
)
]
def print_table(data):
widths = {0:0, 3:len("Language"),2:len("Type"),1:len("Payload")}
for k in data:
for i,d in enumerate(k):
widths[i] = max(widths[i],len(str(d)))
# print(widths)
lan, typ, pay = ["Language","Type","Payload"]
print(f"{lan:<{widths[3]}} | {typ:<{widths[2]}} | {pay:<{widths[1]}}")
# adjust by 10 for ' | ' twice
print("-" * (widths[1]+widths[2]+widths[3]+10))
for k in data:
_, pay, typ, lan = k
print(f"{lan:<{widths[3]}} | {typ:<{widths[2]}} | {pay:<{widths[1]}}")
等效的Python 2.7代码:
# w == widths - would break 79 chars/line else wise
def print_table(data):
w = {0:0, 3:len("Language"),2:len("Type"),1:len("Payload")}
for k in data:
for i,d in enumerate(k):
w[i] = max(w[i],len(str(d)))
lan, typ, pay = ["Language","Type","Payload"]
print "{:<{}} | {:<{}} | {:<{}}".format(lan, w[3], typ, w[2], pay, w[1])
print "-" * (w[1]+w[2]+w[3]+10)
for k in data:
_, pay, typ, lan = k
print "{:<{}} | {:<{}} | {:<{}}".format(lan, w[3], typ, w[2], pay, w[1])
#w==宽度-否则将断开79个字符/行
def打印表格(数据):
w={0:0,3:len(“语言”),2:len(“类型”),1:len(“有效负载”)}
对于k in数据:
对于枚举(k)中的i,d:
w[i]=max(w[i],len(str(d)))
局域网,典型,付费=[“语言”,“类型”,“有效负载”]
打印“{:处理任意列数的解决方案:
from operator import itemgetter
data = [
('ID', 'Payload', 'Type', 'Language'),
(1, u'python -c \'print("ok")\'', u'data', u'python'),
(2, u'python -c \'print("this is some data")\'', u'data', u'python')
]
def print_table(data):
lengths = [
[len(str(x)) for x in row]
for row in data
]
max_lengths = [
max(map(itemgetter(x), lengths))
for x in range(0, len(data[0]))
]
format_str = ''.join(map(lambda x: '%%-%ss | ' % x, max_lengths))
print(format_str % data[0])
print('-' * (sum(max_lengths) + len(max_lengths) * 3 - 1))
for x in data[1:]:
print(format_str % x)
print_table(data)
输出:
Language | Type | Payload
------------------------------------------------------------
python | data | python -c 'print("ok")'
python | data | python -c 'print("this is some data")'
$ python table.py
ID | Payload | Type | Language |
---------------------------------------------------------------
1 | python -c 'print("ok")' | data | python |
2 | python -c 'print("this is some data")' | data | python |
有没有办法不用安装另一个库就可以做到这一点?很抱歉,首先我应该说,有没有办法做到这一点并与2.x和3+兼容?2.x不支持f”“
@13aal您可以将f'strings'
转换为正常的.format()
syntax-请参见编辑-很抱歉没有看到python 2.7标记-python2没有使用print()作为函数-因此它与此方式不兼容-您可能希望将来导入print: