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Python django crispy提交css_类_Python_Django_Twitter Bootstrap - Fatal编程技术网

Python django crispy提交css_类

Python django crispy提交css_类,python,django,twitter-bootstrap,Python,Django,Twitter Bootstrap,我使用django crispy为一个项目呈现表单,并使用bootstrap作为CSS框架。我有以下代码 self.helper.layout = Layout( Fieldset( '', 'username', 'password', ), ButtonHolder( Submit('signin', 'Sign in', css_class='bt

我使用django crispy为一个项目呈现表单,并使用bootstrap作为CSS框架。我有以下代码

self.helper.layout = Layout(
        Fieldset(
            '',
            'username',
            'password',
        ),
        ButtonHolder(
            Submit('signin', 'Sign in', css_class='btn btn-default')
            )
        )
但在HTML中,呈现为

<div class="buttonHolder"><input type="submit" name="signin" value="Sign in" class="btn btn-primary btn btn-default" id="submit-id-signin"/></div>
注意,当我想要btn btn default时,该类是btn btn primary btn btn default

知道为什么会这样吗?谢谢

试试这个:

ButtonHolder(
        Submit('signin', 'Sign in'),
        css_class='btn btn-link'
    )

您应该在回答时提供一些解释,而不仅仅是代码。我随机遇到这个问题,老实说,我看不出问题中的代码与您发布的代码有什么区别。这会将引导样式添加到ButtonHolder而不是按钮。