Python Django筛选器如何更改占位符以替换[无效名称]?
我创建了一个过滤器以在多个字段中搜索(我必须只有一个搜索字段),如下所示: 类myFilter(django_filters.FilterSet): full\u search=django\u filters.CharFilter(name='full\u search',method='search'by\u full\u search') 但在html中,占位符显示了我的诡计Python Django筛选器如何更改占位符以替换[无效名称]?,python,django,django-filters,Python,Django,Django Filters,我创建了一个过滤器以在多个字段中搜索(我必须只有一个搜索字段),如下所示: 类myFilter(django_filters.FilterSet): full\u search=django\u filters.CharFilter(name='full\u search',method='search'by\u full\u search') 但在html中,占位符显示了我的诡计 <input type="text" name="full_search" class="form-cont
<input type="text" name="full_search" class="form-control" placeholder="[invalid name]" title="" id="id_full_search">
是否可以通过其他方式进行更改?最后,我使用JQuery实现了这一点:
$('#id_full_search').attr("placeholder", "Recherche")
我知道这是一段时间前提出的问题,但刚刚解决了一个项目中的类似问题,所以在这里发布它以帮助其他人解决这个问题
full_search = django_filters.CharFilter(method='search_by_full_search', label='Recherche') # change label field to reflect what the filter name should be
class Meta:
model = myModel
fields = ['full_search', ]
def search_by_full_search(self, qs, name, value):
for term in value.split():
qs = qs.filter(Q(serial__icontains=term) | Q(id__icontains=term) |
Q(name__icontains=term))
return qs
full_search = django_filters.CharFilter(method='search_by_full_search', label='Recherche') # change label field to reflect what the filter name should be
class Meta:
model = myModel
fields = ['full_search', ]
def search_by_full_search(self, qs, name, value):
for term in value.split():
qs = qs.filter(Q(serial__icontains=term) | Q(id__icontains=term) |
Q(name__icontains=term))
return qs