Python 特金特环函数
我是GUI编程新手，我正在尝试让这个python程序正常工作。调用函数Python 特金特环函数,python,loops,user-interface,tkinter,Python,Loops,User Interface,Tkinter,我是GUI编程新手，我正在尝试让这个python程序正常工作。调用函数start（）以更新两个画布的正确方法是什么。我的代码看起来像这样 from Tkinter import * class TKinter_test(Frame): def __init__(self,parent): Frame.__init__(self,parent) self.parent = parent self.initUI() user_reply = 0
start（）from Tkinter import *
class TKinter_test(Frame):
def __init__(self,parent):
Frame.__init__(self,parent)
self.parent = parent
self.initUI()
user_reply = 0
def accept(self):
self.user_reply = 1
def decline(self):
self.user_reply = 2
def initUI(self):
BtnFrame = Frame (self.parent)
BtnFrame.place(y=450, x=20)
canvasFrame = Frame(self.parent)
canvasFrame.place(y = 200)
canvas_1 = Canvas(canvasFrame, width = "220", height ="200")
canvas_2 = Canvas(canvasFrame, width = "220", height ="200")
canvas_1.pack(side = LEFT)
canvas_2.pack(side = RIGHT)
textfield_1 = canvas_1.create_text(30,50,anchor = 'w', font =("Helvetica", 17))
textfield_2 = canvas_2.create_text(30,50,anchor = 'w', font =("Helvetica", 17))
Accept = Button(BtnFrame, text="Friends!", width=25, command = self.accept)
Decline = Button(BtnFrame, text="Not friends...", width=25, command = self.decline)
Accept.pack(side = LEFT)
Decline.pack(side = RIGHT)
def ask_user(self,friend_1,friend_2):
timer = 0;
while(timer == 0):
if(self.user_reply == 1):
print friend_1 + " and " + friend_2 + " are friends!"
self.user_reply = 0
timer = 1;
elif(user_reply == 2):
print friend_1 + " and " + friend_2 + " are not friends..."
self.user_reply = 0
timer = 1
def start(self):
listOfPeople = ["John","Tiffany","Leo","Tomas","Stacy","Robin","Carl"]
listOfPeople_2 = ["George","Jasmin","Rosa","Connor","Valerie","James","Bob"]
for friend_1 in listOfPeople:
for friend_2 in listOfPeople_2:
ask_user(friend_1,friend_2)
print "Finished"
def main():
root = Tk()
root.geometry("500x550")
root.wm_title("Tkinter test")
app = TKinter_test(root)
root.mainloop()
if __name__ == '__main__':
main()
textfield\u 1.itemconfigure（text=friend\u 1）谢谢。做事件驱动编程需要不同的心态，一开始可能会有点沮丧和困惑。我建议您查看一下关于堆栈溢出的高分Tkinter答案中的代码，并对其进行实验，进行一些小的更改，看看会发生什么。随着你对它越来越熟悉，它将开始变得有意义 我不知道您为什么需要所有这些
FrameCanvasFrameCanvasLabelfriendlistskwargs帧之前，我们必须从kwargs
中删除该参数。由于该方法将关键字args视为错误，因此无法识别
我创建了一个生成器表达式self.pairs
，它使用doublefor
循环来生成成对的朋友名。调用next（self.pairs）
可以得到下一对朋友的名字
当按下按钮
时，根据按下“friends！”还是“Not friends.”按钮，将调用test_friends
方法，并使用reply
参数True
或False
test\u friends
打印当前一对好友的信息，然后调用set\u friends
方法在标签中设置下一对好友的姓名。如果没有剩余的对，则程序退出
import Tkinter as tk
class MainApplication(tk.Frame):
def __init__(self, parent, *args, **kwargs):
# Extract the friend lists from the keyword args
friends1, friends2 = kwargs['friendlists']
del kwargs['friendlists']
tk.Frame.__init__(self, parent, *args, **kwargs)
self.parent = parent
# A generator that yields all pairs of people from the friends lists
self.pairs = ((u, v) for u in friends1 for v in friends2)
# A pair of labels to display the names
self.friend1 = tk.StringVar()
tk.Label(self, textvariable=self.friend1).grid(row=0, column=0)
self.friend2 = tk.StringVar()
tk.Label(self, textvariable=self.friend2).grid(row=0, column=1)
# Set the first pair of names
self.set_friends()
cmd = lambda: self.test_friends(True)
b = tk.Button(self, text="Friends!", width=25, command=cmd)
b.grid(row=1, column=0)
cmd = lambda: self.test_friends(False)
b = tk.Button(self, text="Not friends.", width=25, command=cmd)
b.grid(row=1, column=1)
def set_friends(self):
# Set the next pair of names
f1, f2 = next(self.pairs)
self.friend1.set(f1)
self.friend2.set(f2)
def test_friends(self, reply):
f1, f2 = self.friend1.get(), self.friend2.get()
reply = (' not ', ' ')[reply]
print '%s and %s are%sfriends' % (f1, f2, reply)
try:
self.set_friends()
except StopIteration:
# No more pairs
print 'Finished!'
self.parent.destroy()
def main():
people_1 = [
"John",
"Tiffany",
"Leo",
"Tomas",
#"Stacy",
#"Robin",
#"Carl",
]
people_2 = [
"George",
"Jasmin",
"Rosa",
#"Connor",
#"Valerie",
#"James",
#"Bob",
]
root = tk.Tk()
root.wm_title("Friend Info")
app = MainApplication(root, friendlists=(people_1, people_2))
app.pack()
root.mainloop()
if __name__ == "__main__":
main()
做事件驱动编程需要不同的思维方式，一开始可能有点令人沮丧和困惑。我建议您查看一下关于堆栈溢出的高分Tkinter答案中的代码，并对其进行实验，进行一些小的更改，看看会发生什么。随着你对它越来越熟悉，它将开始变得有意义
我不知道您为什么需要所有这些Frame
和Canvas
对象，因此我简化了GUI，使用单个Frame
，“借用”Bryan Oakley的模板。我没有使用Canvas
文本项来显示朋友的名字，而是使用简单的Label
小部件
我没有将好友列表硬编码到GUI类中，而是将它们以元组形式作为关键字参数传递给GUI构造函数，friendlists
。在将kwargs
传递到帧之前，我们必须从kwargs
中删除该参数。由于该方法将关键字args视为错误，因此无法识别
我创建了一个生成器表达式self.pairs
，它使用doublefor
循环来生成成对的朋友名。调用next（self.pairs）
可以得到下一对朋友的名字
当按下按钮
时，根据按下“friends！”还是“Not friends.”按钮，将调用test_friends
方法，并使用reply
参数True
或False
test\u friends
打印当前一对好友的信息，然后调用set\u friends
方法在标签中设置下一对好友的姓名。如果没有剩余的对，则程序退出
import Tkinter as tk
class MainApplication(tk.Frame):
def __init__(self, parent, *args, **kwargs):
# Extract the friend lists from the keyword args
friends1, friends2 = kwargs['friendlists']
del kwargs['friendlists']
tk.Frame.__init__(self, parent, *args, **kwargs)
self.parent = parent
# A generator that yields all pairs of people from the friends lists
self.pairs = ((u, v) for u in friends1 for v in friends2)
# A pair of labels to display the names
self.friend1 = tk.StringVar()
tk.Label(self, textvariable=self.friend1).grid(row=0, column=0)
self.friend2 = tk.StringVar()
tk.Label(self, textvariable=self.friend2).grid(row=0, column=1)
# Set the first pair of names
self.set_friends()
cmd = lambda: self.test_friends(True)
b = tk.Button(self, text="Friends!", width=25, command=cmd)
b.grid(row=1, column=0)
cmd = lambda: self.test_friends(False)
b = tk.Button(self, text="Not friends.", width=25, command=cmd)
b.grid(row=1, column=1)
def set_friends(self):
# Set the next pair of names
f1, f2 = next(self.pairs)
self.friend1.set(f1)
self.friend2.set(f2)
def test_friends(self, reply):
f1, f2 = self.friend1.get(), self.friend2.get()
reply = (' not ', ' ')[reply]
print '%s and %s are%sfriends' % (f1, f2, reply)
try:
self.set_friends()
except StopIteration:
# No more pairs
print 'Finished!'
self.parent.destroy()
def main():
people_1 = [
"John",
"Tiffany",
"Leo",
"Tomas",
#"Stacy",
#"Robin",
#"Carl",
]
people_2 = [
"George",
"Jasmin",
"Rosa",
#"Connor",
#"Valerie",
#"James",
#"Bob",
]
root = tk.Tk()
root.wm_title("Friend Info")
app = MainApplication(root, friendlists=(people_1, people_2))
app.pack()
root.mainloop()
if __name__ == "__main__":
main()
不清楚您希望如何执行更新。好吧，每次函数start（）
调用函数ask\u user（）时
我想让它用好友列表的两个名字更新视图，并等待用户通过按钮Accept/Decept@BillalBEGUERADJSorry回答他们是否是好友，因为响应太晚，但希望我的代码会有所帮助。不清楚您希望如何执行更新。好吧，每次函数start（）
调用函数ask_user（）
时，我希望它使用好友列表的两个名称更新视图，并等待用户回答他们是否是好友，按钮接受/拒绝@BillalBEGUERADJSorry，以防响应延迟，但希望我的代码能有所帮助。谢谢！我相信我可以用这个来完成我的程序。谢谢！我肯定我能用这个来完成我的程序。