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Python 作为数据帧名称的名称列出_Python_Pandas - Fatal编程技术网

Python 作为数据帧名称的名称列出

Python 作为数据帧名称的名称列出,python,pandas,Python,Pandas,我想让一些股票符号的名称成为熊猫数据框的实际名称 import pandas as pd import pandas_datareader.data as pdr choices = ['ROK', 'HWM', 'PYPL', 'V', 'KIM', 'FISV', 'REG', 'EMN', 'GS', 'TYL'] for c in choices: pdr.DataReader(c, data_source='yahoo', start=datetime(2000,1,1)

我想让一些股票符号的名称成为熊猫数据框的实际名称

import pandas as pd
import pandas_datareader.data as pdr

choices = ['ROK', 'HWM', 'PYPL', 'V', 'KIM', 'FISV', 'REG', 'EMN', 'GS', 'TYL']

for c in choices:
     pdr.DataReader(c, data_source='yahoo', start=datetime(2000,1,1), 
     end=datetime(2020,1,1)).to_csv(f'Data/{c}.csv')
     f'{c}'['Price'] = pd.read_csv(f'Data/{c}.csv', index_col='Date')['Adj Close']
我得到了这个错误: TypeError:“str”对象不支持项分配

有办法做到这一点吗?也许使用股票符号的名称作为数据帧的名称不是最好的约定


谢谢

您不应该用字符串存储变量,因为它可能会变得非常混乱。若你们想保持你们的惯例,我建议把你们的数据帧存储为一个字典,以股票符号为键

choices = ['ROK', 'HWM', 'PYPL', 'V', 'KIM', 'FISV', 'REG', 'EMN', 'GS', 'TYL']
choices_dict = {}
for c in choices:
     pdr.DataReader(c, data_source='yahoo', start=datetime(2000,1,1), 
     end=datetime(2020,1,1)).to_csv(f'Data/{c}.csv')
     csv_pd = pd.read_csv(f'Data/{c}.csv', index_col='Date')['Adj Close']
     choices_dict[c] = pd.DataFrame(csv_pd, columns=['Price'])

您可以将其作为字典放入数据结构中

import pandas as pd
import pandas_datareader.data as pdr

choices = ['ROK', 'HWM', 'PYPL', 'V', 'KIM', 'FISV', 'REG', 'EMN', 'GS', 'TYL']

dataframes = {}

for c in choices:
     pdr.DataReader(c, data_source='yahoo', start=datetime(2000,1,1), 
     end=datetime(2020,1,1)).to_csv(f'Data/{c}.csv')
     dataframes[c] = pd.read_csv(f'Data/{c}.csv', index_col='Date')['Adj Close']
因此,您将得到一个类似于下面的结构:

>>> print(dataframes)
{'ROK': <your_ROK_dataframe_here>,
 'HWM': <your_HWM_dataframe_here>,
 ...
}
打印(数据帧) {'ROK':, “HWM”:, ... }
然后,您可以使用
dataframes['XXXX']
访问特定的数据帧,其中XXXX是一个选项。

f'{c}'['Price']应该是什么意思?f{c}是一个字符串,所以这就是您看到错误的方式