Python:如果两个单元格都包含某些字符串
我有一个数据帧:Python:如果两个单元格都包含某些字符串,python,dataframe,Python,Dataframe,我有一个数据帧: name alike 0 I love watermelon and banana. melon 1 I love watermelon and banana. banana 2 I love melon. melon 3 I love grape. grape 代码: 输出:
name alike
0 I love watermelon and banana. melon
1 I love watermelon and banana. banana
2 I love melon. melon
3 I love grape. grape
代码:
输出:
name alike
0 I love watermelon and banana. watermelon
1 I love watermelon and banana. watermelon
2 I love melon. melon
3 I love grape. grape
这不是我所期望的结果,我只想在“name”包含西瓜和“like”包含瓜的情况下更改“like”
我试过这样做:
df.loc[df['name'].str.contains('watermelon') and df['alike'].str.contains('melon'), 'alike'] = 'watermelon'
print(df)
错误是这样的:
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
:
或者使用apply(…,axis=1)
就你而言:
df["alike"] = df.apply(
lambda row: "watermelon" if "watermelon" in row["name"] and "melon" in row["alike"] else row["alike"],
axis=1
)
可能重复的
df.loc[df['name'].str.contains('watermelon') & df['alike'].str.contains('melon'), 'alike'] = 'watermelon'
df = pd.DataFrame({
"a": ["hello", "heello", "hello you"],
"b": ["haha", "hehe", "haha hehe"],
"c": ["yes", "yes", "yes"]
})
print(df)
df["c"] = df.apply(
lambda row: row["c"] if "hello" in row["a"] and "hehe" in row["b"] else "no",
axis=1)
print(df)
a b c
0 hello haha yes
1 heello hehe yes
2 hello you haha hehe yes
a b c
0 hello haha no
1 heello hehe no
2 hello you haha hehe yes
df["alike"] = df.apply(
lambda row: "watermelon" if "watermelon" in row["name"] and "melon" in row["alike"] else row["alike"],
axis=1
)