Python 在列中查找关键字并将这些关键字添加到同一行的新列中

我是python新手，这是我关于堆栈溢出的第一篇文章。我有一个关键字列表和一个包含多列的数据框

我想在一个特定的列中搜索这些关键字，并写出与之相对应的关键字

这就是我正在做的

这就是我得到的错误

这就是我想要的

请帮助找出哪里出了问题，或者提出更好的解决方法。谢谢 如果有助于简化工作，请编写下面的代码

import pandas as pd

keywords = ["hello","hi","greetings","wassup"]

data = ["hello, my name is Harry", "Hi I am John", "Yo! Wassup", "Greetings fellow traveller","Hey im 
Henry", "Hello there General Kenobi"]

df = pd.DataFrame(data,columns = ['strings'])

df['Keywords'] = ""

df2 = pd.DataFrame(data = None, columns = df.columns)

for word in keywords:
     temp = df[df['strings'].str.contains(word,na = False)]
     temp.reset_index(drop = True)
     temp['Keywords'] = word
     df2.append(temp)

错误：

C:\Users\harka\Anaconda3\lib\site packages\ipykernel\u launcher.py:5:SettingWithCopyWarning: 试图在数据帧切片的副本上设置值。 尝试改用.loc[row\u indexer，col\u indexer]=value

请参阅文档中的注意事项：

---

“”

我添加了“Yo”以显示它可以返回多个字符串

import pandas as pd

def keyword(row):
  strings = row['strings']
  keywords = ["hello","hi","greetings","wassup",'yo']
  keyword = [key for key in keywords if key.upper() in strings.upper()]
  return keyword

data = ["hello, my name is Harry", "Hi I am John", "Yo! Wassup", "Greetings fellow traveller","Hey im Henry", "Hello there General Kenobi"]

df = pd.DataFrame(data,columns = ['strings'])
df['keyword'] = df.apply(keyword, axis=1)

如果您不喜欢返回的字符串列表，那么可能是逗号分隔的字符串

import pandas as pd

def keyword(row):
  strings = row['strings']
  keywords = ["hello","hi","greetings","wassup",'yo']
  keyword = [key for key in keywords if key.upper() in strings.upper()]
  return ','.join(keyword)

data = ["hello, my name is Harry", "Hi I am John", "Yo! Wassup", "Greetings fellow traveller","Hey im Henry", "Hello there General Kenobi"]

df = pd.DataFrame(data,columns = ['strings'])
df['keyword'] = df.apply(keyword, axis=1)

---

我添加了“Yo”来表示它可以返回多个字符串

import pandas as pd

def keyword(row):
  strings = row['strings']
  keywords = ["hello","hi","greetings","wassup",'yo']
  keyword = [key for key in keywords if key.upper() in strings.upper()]
  return keyword

data = ["hello, my name is Harry", "Hi I am John", "Yo! Wassup", "Greetings fellow traveller","Hey im Henry", "Hello there General Kenobi"]

df = pd.DataFrame(data,columns = ['strings'])
df['keyword'] = df.apply(keyword, axis=1)

如果您不喜欢返回的字符串列表，那么可能是逗号分隔的字符串

import pandas as pd

def keyword(row):
  strings = row['strings']
  keywords = ["hello","hi","greetings","wassup",'yo']
  keyword = [key for key in keywords if key.upper() in strings.upper()]
  return ','.join(keyword)

data = ["hello, my name is Harry", "Hi I am John", "Yo! Wassup", "Greetings fellow traveller","Hey im Henry", "Hello there General Kenobi"]

df = pd.DataFrame(data,columns = ['strings'])
df['keyword'] = df.apply(keyword, axis=1)