Python Django-按属性将查询划分为子组

我有一个这样的模型：

class ListEntry(models.Model):
    STATUS_CHOICES = (
        ('PL', _('Playing')),
        ('CO', _('Completed')),
        ('OH', _('On-hold')),
        ('DR', _('Dropped')),
        ('WA', _('Want to play')),
    )
    user = models.ForeignKey(User)
    game = models.ForeignKey(Game)
    status = models.CharField(_('Status'), max_length=2,
                              choices=STATUS_CHOICES)

class GameListByUserView(ListView):
    model = ListEntry
    template_name = 'game_list_by_user.html'

    def get_queryset(self):
        self.user_profile = get_object_or_404(User, username=self.kwargs['slug'])
        return ListEntry.objects.filter(user=self.user_profile)

    def get_context_data(self, **kwargs):
        context = super(GameListByUserView, self).get_context_data(**kwargs)
        context['user_profile'] = self.user_profile
        return context

在我的视图中，我按用户筛选条目，如下所示：

class ListEntry(models.Model):
    STATUS_CHOICES = (
        ('PL', _('Playing')),
        ('CO', _('Completed')),
        ('OH', _('On-hold')),
        ('DR', _('Dropped')),
        ('WA', _('Want to play')),
    )
    user = models.ForeignKey(User)
    game = models.ForeignKey(Game)
    status = models.CharField(_('Status'), max_length=2,
                              choices=STATUS_CHOICES)

class GameListByUserView(ListView):
    model = ListEntry
    template_name = 'game_list_by_user.html'

    def get_queryset(self):
        self.user_profile = get_object_or_404(User, username=self.kwargs['slug'])
        return ListEntry.objects.filter(user=self.user_profile)

    def get_context_data(self, **kwargs):
        context = super(GameListByUserView, self).get_context_data(**kwargs)
        context['user_profile'] = self.user_profile
        return context

我现在尝试的是根据

status

属性将此查询（

ListEntry.objects.filter（user=self.user\u profile）

）拆分为子组，因此呈现的模板如下所示：

UserFoo's list
=========================

Playing

Game 1
Game 2
Game 3


Completed

Game 4
Game 5
Game 6

我知道我可以做一些事情，比如：

q = ListEntry.objects.filter(user=self.user_profile)
games_dict = {}
games_dict['playing'] = q.filter(status='PL')
games_dict['completed'] = q.filter(status='CO')

依此类推，并迭代模板中的键。或（在模板中）：

但是，没有更好的优化方法来实现这一点，而不必每次按状态获取子查询时都访问数据库，也不必多次迭代对象列表吗？

您正在寻找

{%按状态将对象列表重新组合为游戏列表%}

{游戏中游戏的%u列表%}
{{game.gropper}

{game.list%中项目的%s}
{{item}}
{%endfor%}


{%endfor%}

您可能需要自定义元素的渲染方式，但我会让您自己来解决这个问题