Python 在读取的文件中区分两行

我这样做是为了读取文件

f = subprocess.Popen(["../../../abc/def/run_script.sh", "cat", "def/data/ex/details.json"], stdout=subprocess.PIPE)
out = f.stdout.readline()

从上面读取的文件内容如下所示：

{
         "def1": {
         "val1": 31.6, "val2" : 10
         },
         "def2": {
         "9": {
          "val1": 20.1, "val2": 22
         }
         }
         }

我该怎么做呢。当只有1个“val1”和1个“val2”时，我用regex做了一个简单的搜索并保存了值。既然有两个，我需要小心知道我在对付哪一个。。有没有简单的办法

 File "/usr/lib/python2.7/json/__init__.py", line 338, in loads
                                                                                                                                                               return _default_decoder.decode(s)
                                                                                                                                                                                                  File "/usr/lib/python2.7/json/decoder.py", line 366, in decode
                                                         obj, end = self.raw_decode(s, idx=_w(s, 0).end())
                                                                                                            File "/usr/lib/python2.7/json/decoder.py", line 382, in raw_decode
                                                                                                                                                                                  obj, end = self.scan_once(s, idx)
ValueError: Expecting object: line 1 column 3 (char 2)

用于解析JSON

Python 3代码：

import json
import subprocess

with subprocess.Popen(["cat", "/tmp/foo.json"], stdout=subprocess.PIPE) as f:
    j = f.stdout.read()
o = json.loads(j.decode("UTF-8"))
print(o)
print(o["def1"]["val1"])
print(o["def2"]["9"]["val1"])

{'def1': {'val1': 31.6, 'val2': 10}, 'def2': {'9': {'val1': 20.1, 'val2': 22}}}
31.6
20.1

输出：

import json
import subprocess

with subprocess.Popen(["cat", "/tmp/foo.json"], stdout=subprocess.PIPE) as f:
    j = f.stdout.read()
o = json.loads(j.decode("UTF-8"))
print(o)
print(o["def1"]["val1"])
print(o["def2"]["9"]["val1"])

{'def1': {'val1': 31.6, 'val2': 10}, 'def2': {'9': {'val1': 20.1, 'val2': 22}}}
31.6
20.1

编辑：

import json
import subprocess

with subprocess.Popen(["cat", "/tmp/foo.json"], stdout=subprocess.PIPE) as f:
    j = f.stdout.read()
o = json.loads(j.decode("UTF-8"))
print(o)
print(o["def1"]["val1"])
print(o["def2"]["9"]["val1"])

{'def1': {'val1': 31.6, 'val2': 10}, 'def2': {'9': {'val1': 20.1, 'val2': 22}}}
31.6
20.1

对于Python2，请改用它

import json
import subprocess

f = subprocess.Popen(["cat", "/tmp/foo.json"], stdout=subprocess.PIPE)
j = f.stdout.read()
o = json.loads(j.decode("UTF-8"))
print o
print o["def1"]["val1"]
print o["def2"]["9"]["val1"]

---

鉴于它是JSON，您可以使用您选择的语言中的JSON解析器吗。谢谢你的回复。我该如何构建“s”？。“out”逐行打印文件的cat。

out

不是iter（f.stdout.readline，“”）中i的字符串吗？s=[]：s.append（i）如果我这样做似乎不正确。我似乎不能在这里使用“json.loads（）”。然后呢？。是的，“out”是一行接一行的字符串。我使用您的解决方案编辑了带有错误的问题。你能看看吗，鲁兹？我已经改变了答案。