在Python上编写特定的if-else语句

我正在用Python编写汇编程序，我只需要一些帮助来编写if-else语句。我有下面的机器语言指令，我想转换成二进制

@i

D=M // D=i

@100

D=D-A // D=i-100

如何编写语句，使其删除/忽略注释和空格。在我看来，它将删除/忽略a/后面的任何内容，并跳过该行，直到它到达一个字母，但我不知道如何写这个。

---

谢谢

遵循下面的示例

否则，代码块：

#!/usr/bin/python

var1 = 100
if var1:
   print "1 - Got a true expression value"
   print var1
else:
   print "1 - Got a false expression value"
   print var1

var2 = 0
if var2:
   print "2 - Got a true expression value"
   print var2
else:
   print "2 - Got a false expression value"
   print var2

print "Good bye!"

#!/usr/bin/python

var = 100
if var == 200:
   print "1 - Got a true expression value"
   print var
elif var == 150:
   print "2 - Got a true expression value"
   print var2
elif var == 100:
   print "3 - Got a true expression value"
   print var
else:
   print "4 - Got a false expression value"
   print var

print "Good bye!"

输出：

1 - Got a true expression value
100
2 - Got a false expression value
0
Good bye!

3 - Got a true expression value
100
Good bye!

如果elif else代码块：

#!/usr/bin/python

var1 = 100
if var1:
   print "1 - Got a true expression value"
   print var1
else:
   print "1 - Got a false expression value"
   print var1

var2 = 0
if var2:
   print "2 - Got a true expression value"
   print var2
else:
   print "2 - Got a false expression value"
   print var2

print "Good bye!"

#!/usr/bin/python

var = 100
if var == 200:
   print "1 - Got a true expression value"
   print var
elif var == 150:
   print "2 - Got a true expression value"
   print var2
elif var == 100:
   print "3 - Got a true expression value"
   print var
else:
   print "4 - Got a false expression value"
   print var

print "Good bye!"

输出：

1 - Got a true expression value
100
2 - Got a false expression value
0
Good bye!

3 - Got a true expression value
100
Good bye!

输出：

@i
D=M 
@100
D=D-A