如何在Python中打印字符串内的内容？

我正在使用Python3.8和请求模块测试Rapidapi.com上的API。代码如下：

import requests

url = "https://netflix-unofficial.p.rapidapi.com/api/genres"

headers = {
    'x-rapidapi-host': "netflix-unofficial.p.rapidapi.com",
    'x-rapidapi-key': //here goes my private key
}

response = requests.request("GET", url, headers=headers)

data = response.text

print(data)

我得到的输出如下：

{"data":["Action & Adventure","Anime Features","Children & Family Movies","Classic Movies","Cult Movies","Documentaries","Dramas","Faith & Spirituality","Horror Movies","Independent Movies","International Movies","LGBTQ Movies","Movies","Music & Musicals","Romantic Movies","Sci-Fi & Fantasy","Sports Movies","Stand-Up Comedy","Thrillers"]}

但我希望能够访问列出的每一种流派，并以如下方式展示：

- Genre 1
- Genre 2
...
- Genre n 

---

类型似乎作为数组中的单个元素存储在变量数据中。可以针对数据变量的长度运行循环，然后打印各个元素：

print(data[i])

---

您的字符串如下所示

Gene_Dict = '{"data":["Action & Adventure","Anime Features","Children & Family Movies","Classic Movies","Cult Movies","Documentaries","Dramas","Faith & Spirituality","Horror Movies","Independent Movies","International Movies","LGBTQ Movies","Movies","Music & Musicals","Romantic Movies","Sci-Fi & Fantasy","Sports Movies","Stand-Up Comedy","Thrillers"]}'
Gene_Dict = Gene_Dict.strip()     
Gene_Dict = eval(Gene_Dict)

for ele in Gene_Dict[Gene_Dict.keys()[0]]: print ele

---

您的数据实际上是JSON。您可以将此字符串转换为Python对象，然后对其执行任何操作：

import json

data = '{"data":["Action & Adventure","Anime Features","Children & Family Movies","Classic Movies","Cult Movies","Documentaries","Dramas","Faith & Spirituality","Horror Movies","Independent Movies","International Movies","LGBTQ Movies","Movies","Music & Musicals","Romantic Movies","Sci-Fi & Fantasy","Sports Movies","Stand-Up Comedy","Thrillers"]}'

genres = json.loads(data)['data']
# ['Action & Adventure', 'Anime Features', 'Children & Family Movies', ...]

逐行打印：

print('\n'.join(genres))

或者，如果需要连字符：

print('\n'.join([f'-{genre}' for genre in genres]))

输出：

-Action & Adventure
-Anime Features
-Children & Family Movies
-Classic Movies
...

您可以直接使用

请求

为您操作JSON：

import requests

url = "https://netflix-unofficial.p.rapidapi.com/api/genres"

headers = {
    'x-rapidapi-host': "netflix-unofficial.p.rapidapi.com",
    'x-rapidapi-key': //here goes my private key
}

response = requests.request("GET", url, headers=headers)

data = response.json()
genres = data['data']

---

那么您想打印文本

“-Genre”

，后跟一个数字吗？你是怎么得到这个的？不，我想输出与流派名称并列的连字符（“-”）。我已经尝试过了，但它将元素作为整个字符串的单个字符。由于请求模块中的.text方法，数据未被视为变量。错误：“str”对象没有属性“keys”，在代码中添加了几行以将字符串转换为字典。不要使用

eval

，这是非常糟糕的做法。数据是JSON，应该使用JSON。另外，

Gene_Dict.keys（）[0]

是不必要的，也是危险的，因为1/钥匙是众所周知的，它是

'data'

，2/如果有多个钥匙，就不能保证您会得到正确的钥匙。另外，输出的格式也没有按预期的那样。你可以看看为什么不使用eval。太好了，它成功了！我以前使用ast和eval（）进行过测试，但没有结果。另外，关于

eval

，请查看