在python中删除html标记

所以我正试图从ESPN那里为一场NBA比赛争取一分。我试图先得到名字，但我很难摆脱html标签

我试过使用

get_text(), .text(), .string_strip()

但他们总是给我错误

这是我现在正在使用的代码

from bs4 import BeautifulSoup
import requests

url= "http://scores.espn.com/nba/boxscore?gameId=400900407"
r = requests.get(url)
soup = BeautifulSoup(r.text,"html.parser")

name = []
for row in soup.find_all('tr')[1:]:
        player_name = row.find('td', attrs={'class': 'name'})
        name.append(player_name)
print(name)

使用player_name.text应该可以，但问题是有时row.find'td'，attrs={'class'：'name'}是空的。试着这样做：

if player_name:
     name.append(player_name.text)

使用player_name.text应该可以，但问题是有时row.find'td'，attrs={'class'：'name'}是空的。试着这样做：

if player_name:
     name.append(player_name.text)

---

我这样解决这个问题：

from bs4 import BeautifulSoup
import requests

url= "http://scores.espn.com/nba/boxscore?gameId=400900407"
r = requests.get(url)
soup = BeautifulSoup(r.text,"html.parser")

name = []
for row in soup.find_all('tr')[1:]:
    try:
        player_name = row.select('td.name span')[0].text
        name.append(player_name)
    except:
        pass
print(name)

---

我这样解决这个问题：

from bs4 import BeautifulSoup
import requests

url= "http://scores.espn.com/nba/boxscore?gameId=400900407"
r = requests.get(url)
soup = BeautifulSoup(r.text,"html.parser")

name = []
for row in soup.find_all('tr')[1:]:
    try:
        player_name = row.select('td.name span')[0].text
        name.append(player_name)
    except:
        pass
print(name)

---

我的代码供您参考

import requests

from pyquery import PyQuery as pyq

url= "http://scores.espn.com/nba/boxscore?gameId=400900407"
r = requests.get(url)
doc = pyq(r.content)
print([h.text() for h in doc('.abbr').items()])

---

我的代码供您参考

import requests

from pyquery import PyQuery as pyq

url= "http://scores.espn.com/nba/boxscore?gameId=400900407"
r = requests.get(url)
doc = pyq(r.content)
print([h.text() for h in doc('.abbr').items()])

---

你说错话。什么错误？你说错误。什么错误？