Python 如何用其他数字替换列表元素的索引？

我有一个元素列表，比如说：

A = [1, 2, 3, 4, 5]

B = [(0, 1), (1, 2), (2, 3), (3, 4), (4, 5)]

C = [4, 6, 9, 10 , 22]

B_modified = B = [(4, 1), (6, 2), (9, 3), (10, 4), (22, 5)]

通过使用

enumerate

函数，我将得到如下列表：

A = [1, 2, 3, 4, 5]

B = [(0, 1), (1, 2), (2, 3), (3, 4), (4, 5)]

C = [4, 6, 9, 10 , 22]

B_modified = B = [(4, 1), (6, 2), (9, 3), (10, 4), (22, 5)]

但我想用给定的数字列表替换索引，例如： 如果我有如下列表：

A = [1, 2, 3, 4, 5]

B = [(0, 1), (1, 2), (2, 3), (3, 4), (4, 5)]

C = [4, 6, 9, 10 , 22]

B_modified = B = [(4, 1), (6, 2), (9, 3), (10, 4), (22, 5)]

我想将B更改为如下列表：

A = [1, 2, 3, 4, 5]

B = [(0, 1), (1, 2), (2, 3), (3, 4), (4, 5)]

C = [4, 6, 9, 10 , 22]

B_modified = B = [(4, 1), (6, 2), (9, 3), (10, 4), (22, 5)]

我该怎么做？

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谢谢

您应该使用

zip

功能来组合这两个列表

A = [1, 2, 3, 4, 5]
C = [4, 6, 9, 10 , 22]

B = list(zip(C, A))

print(B)

输出：

[(4, 1), (6, 2), (9, 3), (10, 4), (22, 5)]

4 1
6 2
9 3
10 4
22 5

它可以像枚举一样使用：

for i, e in zip(C, A):
    print(i, e)

输出：

[(4, 1), (6, 2), (9, 3), (10, 4), (22, 5)]

4 1
6 2
9 3
10 4
22 5