Python req.text.find（“”==-1？

我想知道代码的细节。 特别是，为什么req.text.find是-1和req.text[index:index+30]

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好的，让我们看看这个

req = session1.post(URL, cookies=cookie, data=data1)  # Makes a POST request. req now holds the response body
if (req.text.find("Password Incorrect!") == -1):  # Look for the text "Password Incorrect!" in the text of the response body

因此，在python中，有两种方法可以查找字符串中特定子字符串的索引：str.indexsubstr和str.findsubstr。在这两种情况下，如果substr出现在str中，那么这些函数将返回substr开始的str中的索引。它们之间的区别在于，如果substr未出现在str中，则index将引发一个索引器，而find将返回-1

因此，当我们检查req.text.findPassword是否不正确时！==-1，我们正在检查子字符串密码是否不正确！不出现在req.text中

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您是否编写了此代码，如果是，您应该知道它的功能。python查找和字符串切片很容易在documentationWhy reg.text[index:index+30]…？你想知道什么？这句话会导致一些你意想不到的结果吗？你想知道语法吗？

req = session1.post(URL, cookies=cookie, data=data1)  # Makes a POST request. req now holds the response body
if (req.text.find("Password Incorrect!") == -1):  # Look for the text "Password Incorrect!" in the text of the response body

if (req.text.find("Password Incorrect!") == -1):  # continuing on...
    index = req.text.find("Authkey")              # Find the index of the string "AuthKey" in req.text
    print("\n\n")
    print(req.text[index:index+30])               # print the contents of `req.text` from that index
    print("\n\n")                                 #   through the next 30 characters
    input("Press Any KEY to exit.......")         # and finally, exit
    exit(0)
else:
    print("Wrong Num :" + str(i))                 # If we DO find "Password Incorrect!" in req.text,
                                                  #   then we just say "Wrong Number" and continue on with the loop.