Python 在Django中为类方法制作装饰器

我发现基于函数的视图需要staff\u member\u，但没有找到类方法。我试图为基于类的视图编写decorator：

from django.contrib.admin.views.decorators import staff_member_required
from django.views.generic import View

def cls_method_staff_member_decorator(func):
    def wrapper(self, request, *args, **kwargs):
        return staff_member_required(view_func=func)(request, *args, **kwargs)
    return wrapper

class SetUserData(View):
    http_method_names = ['get', ]

    @cls_method_staff_member_decorator
    def get(self, request, user_id):
        # ... some actions with data

但在通过runserver命令启动服务器后，出现以下错误：

/en us/user/userdata/7/get处的TypeError正好取3 论据2

如何修复它？

您需要使用decorator方法装饰分派方法

解释

或者在URL中修饰：

class SetUserData(View):
    @method_decorator(cls_method_staff_member_decorator)
    def dispatch(self, *args, **kwargs):
        return super(SetUserData, self).dispatch(*args, **kwargs)

urlpatterns = patterns('',
    ...
    (r'^your_url/', cls_method_staff_member_decorator(SetUserData.as_view())),
    ...
)