如何创建'；集合列表'；从a'；python中的列表'；？

假设我有一个列表：

[["blue","red","green"],["red","red","yellow"],["blue,"blue","green"]]

我想创建一个集合列表，如：

[{"blue","red","green"},{"red","yellow"},{"blue,"green"}]

我该怎么做呢？

你可以这样做

a = [["blue","red","green"],["red","red","yellow"],["blue","blue","green"]]

b = [set(i) for i in a]
print(b)

您可以使用

map（）

您可以使用：

  b = list(map(set, a))

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循环浏览顶部列表并将每个子列表转换为一个集合

myList = [["blue","red","green"],["red","red","yellow"],["blue","blue","green"]]

for i in range(len(myList)):
    myList[i] = set(myList[i])

或者是单程票

myList = [["blue","red","green"],["red","red","yellow"],["blue","blue","green"]]
myList = [set(i) for i in myList]

---

第一：如何在python中将列表转换为集合

my_list = ["blue","red","green"]

my_set_from_list = set(my_list)

print(my_set_from_list)

第二，如何从列表列表推广到集合列表：

list_lists = [["blue","red","green"],["red","red","yellow"],["blue","blue","green"]]

list_sets = []

for one_list in list_lists:
    list_sets.append(set(one_list))

print(list_sets)

第三：如何压缩代码（来自@Ahmed Mamdouh的答案）：

---

祝你好运：）

你尝试了什么？那一个

“

是如何丢失的？字符串是可散列的，因此每个内部列表都可以轻松转换为一个集合。你到底遇到了什么问题？

list_lists = [["blue","red","green"],["red","red","yellow"],["blue","blue","green"]]

list_sets = []

for one_list in list_lists:
    list_sets.append(set(one_list))

print(list_sets)

list_lists = [["blue","red","green"],["red","red","yellow"],["blue","blue","green"]]

list_sets = [set(one_list) for one_list in list_lists]

print(list_sets)