Python 如何将参数传递到构造函数中?
此代码:Python 如何将参数传递到构造函数中?,python,Python,此代码: class Net(nn.Module): def __init__(self): super(Net, self).__init__() self.conv1 = nn.Conv2d(1,6,5) self.conv2 = nn.Conv2d(6, 16, 5) self.fc1 = nn.Linear(16*5*5, 120) self.fc2 = nn.Linear(120, 84)
class Net(nn.Module):
def __init__(self):
super(Net, self).__init__()
self.conv1 = nn.Conv2d(1,6,5)
self.conv2 = nn.Conv2d(6, 16, 5)
self.fc1 = nn.Linear(16*5*5, 120)
self.fc2 = nn.Linear(120, 84)
self.fc3 = nn.Linear(84, 10)
def forward(self, x):
x = F.max_pool2d(F.relu(self.conv1(x)), (2,2))
x = F.max_pool2d(F.relu(self.conv2(x)), 2)
x = x.view(-1, self.num_flat_features(x))
x = F.relu(self.fc1(x))
x = F.relu(self.fc2(x))
x = self.fc3(x)
return x
def num_flat_features(self, x):
size = x.size()[1:]
num_features = 1
for s in size:
num_features *= s
return num_features
net = Net()
input = torch.randn(1,1,32,32)
out = net(input)
print(out)
我正在学习python并试图理解这个构造函数是如何工作的。我的问题有两行:
input = torch.randn(1,1,32,32)
out = net(input)
在init初始化中,我看不到如何使用“input”进行初始化
net = Net()
在不带参数的情况下调用_init__方法
out = net(input)
以输入为参数调用_call__方法。
由于Net没有实现这一点,它必须在基类nn.Module中实现
您可以找到nn.Module的源,并且有一个用输入作为参数定义的调用。您不是在向类传递参数,而是在向对象传递参数。有区别 下面的示例显示了如何实现这一点。您需要实现调用方法 查看“调用”方法在哪里搜索呼叫__
class CallableClass:
def __init__(self):
pass
def __call__(self, *args, **kwargs):
print(args)
class Net(CallableClass):
def __init__(self):
super(Net, self).__init__()
pass
net = Net()
net(100)