Python名称错误：名称''；没有定义

我对python相当陌生，我创建了这段代码用于受控评估，但它表明“q11”（第一个web打开命令）没有定义。它和其他的一样，以前工作得很好，但现在我又开始工作了，但它就是不工作

先谢谢你

这是我的密码：

import webbrowser
import random
sol1 = ("Check if there is lint in the charging ports. This can be removed            carefully with a toothpick or similar implement")
sol2 = ("Turn on assistive touch if you have an iphone (settings > general >    accessability > assistive touch until you go to a shop to get them replaced. If  you use android, download 'button savior' from the google play store")
sol3 = ("Do a hard reset - hold down the power and home buttons until the screen  turns off and keep them held down until the screen turns on again ")
sol4 = ("Restore the phone to factory settings and set it up as new")
sol5 = ("You need a screen replacement.")
sol6 = ("You may need to replace the battery.")
sol7 = ("You dont need to do anything. Your phone doesnt have any problems.")
sol8 = ("Please update your phone software.")
sol9 = ("Contact apple for support")
sol10 = ("Take the phone and put it in a bag of rice for  24-36 hours to let the rice absorb the water.")


q1=input("Is your phone charging correctly? ")
 if q1 == "no":
    print(sol1)
if q1 == "yes":

q2=input("Is your phone water damaged? ")
  if q2 == "yes":
      print(sol10)
if q2 == "no":

q3=input("Is the screen cracked or badly scratched? ")
 if q3 == "yes":
     print(sol5)
if q3 == "no":

q4=input("Is the phone working slowly and crashing? ")
 if q4 == "yes":
     print(sol3)
if q4 == "no":

q5=input("Do you wish to remove data from the phone? ")
 if q5 == "yes":
     print(sol4)
if q5 == "no":

q6=input("Does the phone work without issues? ")
 if q6 == "yes":
     print(sol7)
if q6 == "no":

q7=input("Are you running the lastest software version? ")
  if q7 == "no":
     print(sol8)
if q7 == "yes":

q8=input("Are the buttons producing accurate responses ")
 if q8 == "no":
     print(sol2)
if q8 == "yes":

q9=input("Is your phone battery draining and dying early? ")
 if q9 == "yes":
    print(sol6)
if q9 == "no":

q10=input("Does the phone turn on, even if it has been charged with a working charger? ")
 if q10 == "yes":
     print(sol9)
if q10 == "no":

q11=input("Would you like to visit the apple support site?: yes/no ")
 if q11 == "yes":
      webbrowser.open("https://support.apple.com/en-gb")
if q11 == "no":

q12=input("Would you like to visit the genius bar booking site?: yes/no ")
 if q12 == "yes":
      webbrowser.open("https://getsupport.apple.com/")
 if q12 == "no":

---

print（“感谢您使用此服务。我们希望您觉得它很有用”）

好的，您已经为此工作了一段时间，我添加了以下代码：

list = []
q1 = str(input("Is your phone charging correctly? "))
characters = len(q1)
for i in range(characters):
    lowercase = str.lower(q1[i])
    list.append(lowercase)
q1 = ("".join(list))

characters变量统计在q1中输入的字符数，例如，如果他们键入“是”，将计3个字符，“否”，将计2个字符，等等

这个小写变量基本上设置了他们输入的所有内容，并通过整个字符串进行小写循环。我们创建了循环字符数的for循环。（例如：他们输入'YES'，然后长度将保存为3，并循环字符串'YES'中的每个字符，将其全部更改为'YES'

我们需要字符串长度的原因是，没有它，我们无法循环正确的次数。（例如：如果我们只放置一个2的循环，那么如果他们输入“是”，它将只遍历字符串两次，并将另存为“ye”，而不包括第三个字符。如果循环为2，则将其另存为“y”

list.append(lowercase)

This list.append基本上是将第一个循环中的字母“y”添加到类似于['y']的列表中，然后在第二个循环中添加类似于['y'，'e']的字母“e”，以及第三个循环['y'，'e'，'s']

q1 = ("".join(list))

这一部分基本上把我们刚才列出的['y'，'e'，'s']组合成一个名为q1的字符串，它是你答案的变量。它把它组合成'yes'

我之所以在第一个地方添加改为小写，是因为如果他们输入‘是’或‘是’或‘是’……等等，它将始终改为所有小写，以便答案仍然有效

import webbrowser
import random
sol1 = ("Check if there is lint in the charging ports. This can be removed                carefully with a toothpick or similar implement")
sol2 = ("Turn on assistive touch if you have an iphone (settings > general >    accessability > assistive touch until you go to a shop to get them replaced. If  you use android, download 'button savior' from the google play store")
sol3 = ("Do a hard reset - hold down the power and home buttons until the screen  turns off and keep them held down until the screen turns on again ")
sol4 = ("Restore the phone to factory settings and set it up as new")
sol5 = ("You need a screen replacement.")
sol6 = ("You may need to replace the battery.")
sol7 = ("You dont need to do anything. Your phone doesnt have any problems.")
sol8 = ("Please update your phone software.")
sol9 = ("Contact apple for support")
sol10 = ("Take the phone and put it in a bag of rice for  24-36 hours to let the rice absorb the water.")

list = []
q1 = str(input("Is your phone charging correctly? "))
characters = len(q1)
for i in range(characters):
    lowercase = str.lower(q1[i])
    list.append(lowercase)
q1 = ("".join(list))
if q1 == "no":
    print(sol1)

list = []
if q1 == "yes":
    q2 = str(input("Is your phone water damaged? "))
for i in range(len(q2)):
    lowercase = str.lower(q2[i])
    list.append(lowercase)
q2 = ("".join(list))
if q2 == "yes":
    print(sol10)

list = []
if q2 == "no":
    q3 = str(input("Is the screen cracked or badly scratched? "))
    for i in range(len(q3)):
        lowercase = str.lower(q3[i])
        list.append(lowercase)
q3 = ("".join(list))
if q3 == "yes":
    print(sol5)

list = []
if q3 == "no":
    q4 = str(input("Is the phone working slowly and crashing? "))
    for i in range(len(q4)):
        lowercase = str.lower(q4[i])
        list.append(lowercase)
q4 = ("".join(list))
if q4 == "yes":
    print(sol3)

list = []
if q4 == "no":
    q5 = str(input("Do you wish to remove data from the phone? "))
    for i in range(len(q5)):
        lowercase = str.lower(q5[i])
        list.append(lowercase)
q5 = ("".join(list))
if q5 == "yes":
    print(sol4)

list = []
if q5 == "no":
    q6 = str(input("Does the phone work without issues? "))
    for i in range(len(q6)):
        lowercase = str.lower(q6[i])
        list.append(lowercase)
q6 = ("".join(list))
if q6 == "yes":
    print(sol7)

list = []
if q6 == "no":
    q7 = str(input("Are you running the lastest software version? "))
    for i in range(len(q7)):
        lowercase = str.lower(q7[i])
        list.append(lowercase)
q7 = ("".join(list))
if q7 == "no":
    print(sol8)

list = []
if q7 == "yes":
    q8 = str(input("Are the buttons producing accurate responses "))
    for i in range(len(q8)):
        lowercase = str.lower(q8[i])
        list.append(lowercase)
q8 = ("".join(list))
if q8 == "no":
     print(sol2)

list = []
if q8 == "yes":
    q9 = str(input("Is your phone battery draining and dying early? "))
    for i in range(len(q9)):
        lowercase = str.lower(q9[i])
        list.append(lowercase)
q9 = ("".join(list))
if q9 == "yes":
    print(sol6)

list = []
if q9 == "no":
    q10 = str(input("Does the phone turn on, even if it has been charged with a working charger? "))
    for i in range(len(q10)):
        lowercase = str.lower(q10[i])
        list.append(lowercase)
q10 = ("".join(list))
if q10 == "yes":
     print(sol9)

list = []
if q10 == "no":
    q11 = str(input("Would you like to visit the apple support site?: yes/no "))
    for i in range(len(q11)):
        lowercase = str.lower(q11[i])
        list.append(lowercase)
q11 = ("".join(list))
if q11 == "yes":
    webbrowser.open("https://support.apple.com/en-gb")

list = []
if q11 == "no":
    q12 = str(input("Would you like to visit the genius bar booking site?: yes/no "))
    for i in range(len(q12)):
        lowercase = str.lower(q12[i])
        list.append(lowercase)
q12 = ("".join(list))

if q12 == "yes":
    webbrowser.open("https://getsupport.apple.com/")
else:
    print()

---

或者，您可以让他们输入y或n，这将大大减少代码行数

与我之前的答案不同的是，我只是让它循环一次，将“Y”改为小写，或将“N”改为小写。最好是这样做，因为当人们使用程序并被要求输入“Y”时，他们有时会改为输入“Y”，所以最好确定

同样，在同一事物上添加elif而不是if作为第二个if语句是一种更简洁的编程方式，虽然python允许这样做，但如果您继续使用另一种编程语言，您必须使用elif，因此现在也可以习惯它了

sol1 = ("Check if there is lint in the charging ports. This can be removed            carefully with a toothpick or similar implement")

另一个技巧是，可以将上面的这个变量变成比大量空格要好得多的东西，你知道吗？字符串中的“\n”开始一个新行

import webbrowser
import random
sol1 = ("Check if there is lint in the charging ports. This can be removed\ncarefully with a toothpick or similar implement")
sol2 = ("Turn on assistive touch if you have an iphone (settings > general >\naccessability > assistive touch until you go to a shop to get them replaced If  you use android, download 'button savior' from the google play store")
sol3 = ("Do a hard reset - hold down the power and home buttons until the screen\nturns off and keep them held down until the screen turns on again ")
sol4 = ("Restore the phone to factory settings and set it up as new")
sol5 = ("You need a screen replacement.")
sol6 = ("You may need to replace the battery.")
sol7 = ("You dont need to do anything. Your phone doesnt have any problems.")
sol8 = ("Please update your phone software.")
sol9 = ("Contact apple for support")
sol10 = ("Take the phone and put it in a bag of rice for\n24-36 hours to let the rice absorb the water.")

q1 = str(input("Is your phone charging correctly? Y/N >> "))
for i in range(1):
    q1 = str.lower(q1)
if q1 == "n":
    print(sol1)

elif q1 == "y":
    q2 = str(input("Is your phone water damaged? Y/N >> "))
    for i in range(1):
        q2 = str.lower(q2)
if q2 == "y":
    print(sol10)

elif q2 == "n":
    q3 = str(input("Is the screen cracked or badly scratched? Y/N >> "))
    for i in range(1):
        q3 = str.lower(q3)
if q3 == "y":
    print(sol5)

elif q3 == "n":
    q4 = str(input("Is the phone working slowly and crashing? Y/N >> "))
    for i in range(1):
        q4 = str.lower(q4)
if q4 == "y":
    print(sol3)

elif q4 == "n":
    q5 = str(input("Do you wish to remove data from the phone? Y/N >> "))
    for i in range(1):
         q5 = str.lower(q5)
if q5 == "y":
    print(sol4)

elif q5 == "n":
    q6 = str(input("Does the phone work without issues? Y/N >> "))
    for i in range(1):
        q6 = str.lower(q6)
if q6 == "y":
    print(sol7)

elif q6 == "n":
    q7 = str(input("Are you running the lastest software version? Y/N >> "))
    for i in range(1):
        q7 = str.lower(q7)
if q7 == "n":
    print(sol8)

elif q7 == "y":
    q8 = str(input("Are the buttons producing accurate responses Y/N >> "))
    for i in range(1):
        q8 = str.lower(q8)
if q8 == "n":
     print(sol2)

elif q8 == "y":
    q9 = str(input("Is your phone battery draining and dying early? Y/N >> "))
    for i in range(1):
        q9 = str.lower(q9)
if q9 == "y":
    print(sol6)

elif q9 == "n":
    q10 = str(input("Does the phone turn on, even if it has been charged with a working charger? Y/N >> "))
    for i in range(1):
        q10 = str.lower(q10)
if q10 == "y":
     print(sol9)

elif q10 == "n":
    q11 = str(input("Would you like to visit the apple support site?: yes/no Y/N >> "))
    for i in range(1):
        q11 = str.lower(q11)
if q11 == "y":
    webbrowser.open("https://support.apple.com/en-gb")

elif q11 == "n":
    q12 = str(input("Would you like to visit the genius bar booking site?:  Y/N >> "))
    for i in range(1):
        q12 = str.lower(q12)

if q12 == "y":
    webbrowser.open("https://getsupport.apple.com/")
else:
    print()

---

您甚至可以使用字典来删除所有这些变量，如sol1、sol2、sol3。这样的编码非常混乱，效率低下。请尝试使用以下字典：

solutions = {1: "Check if there is lint in the charging ports. This can be removed\ncarefully with a toothpick or similar implement",
         2: "Turn on assistive touch if you have an iphone (settings > general >\naccessability > assistive touch until you go to a shop to get them replaced If  you use android, download 'button savior' from the google play store.",
         3: "Do a hard reset - hold down the power and home buttons until the screen\nturns off and keep them held down until the screen turns on again ",
         4: "Restore the phone to factory settings and set it up as new",
         5: "You need a screen replacement.",
         6: "You may need to replace the battery.",
         7: "You dont need to do anything. Your phone doesnt have any problems.",
         8: "Please update your phone software.",
         9: "Contact apple for support",
         10: "Take the phone and put it in a bag of rice for\n24-36 hours to let the rice absorb the water."
         }

它基本上分配了数字1:‘这里的字符串’和2:‘这里的字符串’。这对于您尝试执行的操作非常有用，因为加载变量并不是一件聪明的事情，因为它们可能会让人困惑等等

但要让它打印出正确的解决方案，您只需打印解决方案1的（解决方案[1]），或打印解决方案2的（解决方案[2]）。希望这能有所帮助

完整代码：

solutions = {1: "Check if there is lint in the charging ports. This can be removed\ncarefully with a toothpick or similar implement",
         2: "Turn on assistive touch if you have an iphone (settings > general >\naccessability > assistive touch until you go to a shop to get them replaced If  you use android, download 'button savior' from the google play store.",
         3: "Do a hard reset - hold down the power and home buttons until the screen\nturns off and keep them held down until the screen turns on again ",
         4: "Restore the phone to factory settings and set it up as new",
         5: "You need a screen replacement.",
         6: "You may need to replace the battery.",
         7: "You dont need to do anything. Your phone doesnt have any problems.",
         8: "Please update your phone software.",
         9: "Contact apple for support",
         10: "Take the phone and put it in a bag of rice for\n24-36 hours to let the rice absorb the water."
         }
q1 = str(input("Is your phone charging correctly? Y/N >> "))
for i in range(1):
    q1 = str.lower(q1)
if q1 == "n":
    print(solutions[1])

elif q1 == "y":
    q2 = str(input("Is your phone water damaged? Y/N >> "))
    for i in range(1):
        q2 = str.lower(q2)
    if q2 == "y":
        print(solutions[2])

elif q2 == "n":
    q3 = str(input("Is the screen cracked or badly scratched? Y/N >> "))
    for i in range(1):
        q3 = str.lower(q3)
    if q3 == "y":
        print(solutions[3])

elif q3 == "n":
    q4 = str(input("Is the phone working slowly and crashing? Y/N >> "))
    for i in range(1):
        q4 = str.lower(q4)
    if q4 == "y":
        print(solutions[4])

elif q4 == "n":
    q5 = str(input("Do you wish to remove data from the phone? Y/N >> "))
    for i in range(1):
        q5 = str.lower(q5)
    if q5 == "y":
        print(solutions[4])

elif q5 == "n":
    q6 = str(input("Does the phone work without issues? Y/N >> "))
    for i in range(1):
        q6 = str.lower(q6)
    if q6 == "y":
        print(solutions[7])

elif q6 == "n":
    q7 = str(input("Are you running the lastest software version? Y/N >> "))
    for i in range(1):
        q7 = str.lower(q7)
    if q7 == "n":
        print(solutions[8])

elif q7 == "y":
    q8 = str(input("Are the buttons producing accurate responses Y/N >> "))
    for i in range(1):
        q8 = str.lower(q8)
    if q8 == "n":
         print(solutions[2])

elif q8 == "y":
    q9 = str(input("Is your phone battery draining and dying early? Y/N >> "))
    for i in range(1):
        q9 = str.lower(q9)
    if q9 == "y":
        print(solutions[6])

elif q9 == "n":
    q10 = str(input("Does the phone turn on, even if it has been charged with a working charger? Y/N >> "))
    for i in range(1):
        q10 = str.lower(q10)
    if q10 == "y":
         print(solutions[9])

elif q10 == "n":
    q11 = str(input("Would you like to visit the apple support site?: yes/no Y/N >> "))
    for i in range(1):
        q11 = str.lower(q11)
    if q11 == "y":
        webbrowser.open("https://support.apple.com/en-gb")

elif q11 == "n":
    q12 = str(input("Would you like to visit the genius bar booking site?:  Y/N >> "))
    for i in range(1):
        q12 = str.lower(q12)

    if q12 == "y":
        webbrowser.open("https://getsupport.apple.com/")
    else:
        print()

---

请修复缩进。1）期望最终用户准确输入“是”或“否”是有风险的。您可能想将问题改为

手机是否工作缓慢且崩溃？（是/否）

以确保用户回答了您希望他回答的问题。2） 这些级联的

if

是糟糕的设计。将

打印

更改为

返回

，并删除对变量的第二个测试。请询问我您可能有的任何问题。我目前正在使用您的代码，我将其标记为最佳答案。然而，网页链接不会打开，代码在第10个问题之后就结束了。这以前发生过，语法与其他问题相同。你知道为什么会发生这种情况吗？我在这两个代码版本上花了很多时间，选择一个你最了解/与你的课程工作最相关的。祝你好运，有问题问我：太感谢你了！这真的很有帮助，5）/“谢谢你的时间：）设一个为最佳答案？好了，我添加了3个答案。这个答案是最好的，字典更实用，也不那么凌乱。