Python 类型错误:';在<;字符串>';需要字符串作为左操作数,而不是列表
我正在为我的GCSE计算项目创建一个刽子手游戏。我遇到了一个我似乎无法纠正的错误 以下是所有代码:Python 类型错误:';在<;字符串>';需要字符串作为左操作数,而不是列表,python,python-3.x,Python,Python 3.x,我正在为我的GCSE计算项目创建一个刽子手游戏。我遇到了一个我似乎无法纠正的错误 以下是所有代码: import random #Creates a tuple with words in WORDS = ("church","smelly","chicks") #This picks a word randomly word = random.choice(WORDS) print("The word is", len(word), "letters long.") #This is
import random
#Creates a tuple with words in
WORDS = ("church","smelly","chicks")
#This picks a word randomly
word = random.choice(WORDS)
print("The word is", len(word), "letters long.")
#This is the game
for i in range(1):
letter1 = input ("Guess a letter:")
if letter1 in word:
print("Correct. This letter is in the word")
else:
print("Incorrect. This letter is not in the word.")
for i in range(1):
letter2 = input ("Guess a letter:")
if letter2 in word:
print("Correct. This letter is in the word")
else:
print("Incorrect. This letter is not in the word.")
for i in range(1):
letter3 = input ("Guess a letter:")
if letter3 in word:
print("Correct. This letter is in the word")
else:
print("Incorrect. This letter is not in the word.")
for i in range(1):
letter4 = input ("Guess a letter:")
if letter4 in word:
print("Correct. This letter is in the word")
else:
print("Incorrect. This letter is not in the word.")
for i in range(1):
letter5 = input ("Guess a letter:")
if letter5 in word:
print("Correct. This letter is in the word")
else:
print("Incorrect. This letter is not in the word.")
for i in range(1):
letter6 = input ("Guess a letter:")
if letter6 in word:
print("Correct. This letter is in the word")
else:
print("Incorrect. This letter is not in the word.")
all_letters = [letter1, letter2, letter3, letter4, letter5, letter6]
# Conditions for winning/losing
if all_letters in word:
print("Well done, you got it.")
else:
print("Sorry, You are the loser.")
当我运行程序时,我得到了这个错误
TypeError: 'in <string>' requires string as left operand, not list
TypeError:'in'需要字符串作为左操作数,而不是列表
我不知道如何修复这个错误,有人能帮我吗
另外,如果你能,你能给我一些建议来改进整个代码的任何部分吗
*这是我的第一个问题,如果我说得太多,请原谅我“您应该按照以下步骤来做:
if all(i in word for i in all_letters):
print("Well done, you got it.")
else:
print("Sorry, You are the loser.")
这将打印
“做得好,你做到了。”
仅当所有字母都在word中时。它使用所有内置的。为什么要对范围(1)中的i执行
?向我们展示完整的堆栈跟踪。@user2357112所以每个变量接受一个字母不管你认为循环在做什么,它可能没有做什么。循环完全等同于根本没有循环,只需设置i=0
@user2357112我不确定该做什么,这是我让我的刽子手游戏给出答案的唯一方法输入的每个字母的ponse。