如何从R中的矩阵创建边列表？

关系表示为矩阵

x

，如下所示：

      A    B    C     D
A     0    2    1     1
B     2    0    1     0
C     1    1    0     1
D     1    0    1     0

这些条目指的是它们拥有的连接数

有人能告诉我如何把它写成边缘列表吗

我更愿意将其写为边缘列表：

A B
A B
A C
A D
B C

---

但是此边缘列表允许我创建网络图吗？

使用

igraph

软件包：

x <- matrix(c(0,2,1,1,2,0,1,0,1,1,0,1,1,0,1,0), 4, 4)
rownames(x) <- colnames(x) <- LETTERS[1:4]

library(igraph)
g <- graph.adjacency(x)
get.edgelist(g)

#      [,1] [,2]
#  [1,] "A"  "B" 
#  [2,] "A"  "B" 
#  [3,] "A"  "C" 
#  [4,] "A"  "D" 
#  [5,] "B"  "A" 
#  [6,] "B"  "A" 
#  [7,] "B"  "C" 
#  [8,] "C"  "A" 
#  [9,] "C"  "B" 
# [10,] "C"  "D" 
# [11,] "D"  "A" 
# [12,] "D"  "C"

x试试这个

M <- matrix( c(0,2,1,1,2,0,1,0,1,1,0,1,1,0,1,0), 4, 4, dimnames=list(c("A","B","C","D"), c("A","B","C","D")))

eList <- NULL
for ( i in 1:nrow(M) ){
  for ( j in 1:ncol(M)) {
    eList <- c(eList, rep(paste(dimnames(M)[[1]][i], dimnames(M)[[2]][j] ), M[i,j]))
  }
}

在
重塑2
中使用
melt
，然后删除权重==0。如果不需要打印重量。删除它就行了

x
    sample1 sample2 sample3 sample4
feature1       0       2       1       1
feature2       2       0       1       0
feature3       1       1       0       1
feature4       1       0       1       0

melt(x)
   Var1    Var2 value
1  feature1 sample1     0
2  feature2 sample1     2
3  feature3 sample1     1
4  feature4 sample1     1
5  feature1 sample2     2

谢谢你的帮助！我现在正在阅读你推荐的文件。你的解决方案反过来又是什么？我的意思是，如果我们有一个边列表，想用你的方式把它转换成一个邻接矩阵？
x
    sample1 sample2 sample3 sample4
feature1       0       2       1       1
feature2       2       0       1       0
feature3       1       1       0       1
feature4       1       0       1       0

melt(x)
   Var1    Var2 value
1  feature1 sample1     0
2  feature2 sample1     2
3  feature3 sample1     1
4  feature4 sample1     1
5  feature1 sample2     2