R有效地计数频率
假设我有一个问题,我有一个向量,叫做,基,定义为R有效地计数频率,r,R,假设我有一个问题,我有一个向量,叫做,基,定义为 bases <- c(1:100000) bases本质上,您是在寻找直方图。使用hist功能 bases <- c(1:100000) instances <- c(12, 367, 442, 551, 1882, 2556, 13222, 13772, 18999, 26000, 29004, 83027) # plot = 0 prevents plotting # breaks ar
bases <- c(1:100000)
bases本质上,您是在寻找直方图。使用hist
功能
bases <- c(1:100000)
instances <- c(12, 367, 442, 551, 1882, 2556, 13222, 13772,
18999, 26000, 29004, 83027)
# plot = 0 prevents plotting
# breaks are the values at which we want to split our interval
h <- hist(instances, breaks = seq(0, max(bases), 1000), plot=0)
base查看findInterval
和cut
…可能还有table
或tablate
。我认为这是最有效和明智的方法,因为我计划稍后绘制直方图:)
bases <- c(1:100000)
instances <- c(12, 367, 442, 551, 1882, 2556, 13222, 13772,
18999, 26000, 29004, 83027)
# plot = 0 prevents plotting
# breaks are the values at which we want to split our interval
h <- hist(instances, breaks = seq(0, max(bases), 1000), plot=0)