R CSS选择器读取用户评级

网站： 目标：提取个人用户评分

当我检查用户评级时，我看到了这一点

<span class="staticStars notranslate" title="did not like it">

如果我可以提取标题，我就可以绘制收视率

rate_map = {'did not like it': 1,
'it was ok': 2,
'liked it': 3,
'really liked it': 4,
'it was amazing': 5}

url = 'https://www.goodreads.com/book/show/27841061-nevernight'
gr_list <- read_html(url)
gr_list %>%  html_node('.staticStars .notranslate') %>%  
  html_attr('title')

rate_map={'不喜欢它：1，
“还行”：2，
“喜欢它”：3，
“真的很喜欢”：4，
“太棒了”：5}
url='1〕https://www.goodreads.com/book/show/27841061-nevernight'
gr_列表%html_节点（'.staticStars.NotTranslate'）%>%
html_attr（'标题'）

代码的结果是“NA”

谁能告诉我我做错了什么？

---

谢谢。

css选择器

.statisticstars.nottranslate

表示您正在查找一个类

nottranslate

嵌套在类

statisticstars

节点中的节点。也就是说，它会匹配这样的东西

<span class="staticStars"><span class="notranslate">foo</span></span>

foo

如果要匹配具有两个类的节点，则需要确保选择器之间没有空格。你能行

url <- 'https://www.goodreads.com/book/show/27841061-nevernight'
gr_list <- read_html(url)
gr_list %>%  html_nodes('.staticStars.notranslate') %>% 
  html_attr('title')

#  [1] NA                NA                "did not like it"
#  [4] "did not like it" "it was amazing"  "it was amazing" 
#  [7] "it was amazing"  "it was amazing"  "it was amazing" 
# [10] "did not like it" "it was amazing"  "really liked it"
# [13] "did not like it" "it was amazing"  "it was amazing" 
# [16] "it was amazing"  "did not like it" "it was amazing" 
# [19] "it was amazing"  "it was amazing"  "it was amazing" 
# [22] "it was amazing"  "it was amazing"  "it was amazing" 
# [25] "it was amazing"  "it was amazing"  "it was amazing" 
# [28] "it was amazing"  "it was amazing"  "liked it" 

url%
html_attr（'标题'）
#[1]娜娜“不喜欢”
#[4]“不喜欢它”“太棒了”“太棒了”
#[7]“太棒了”“太棒了”“太棒了”
#[10]“不喜欢它”“太棒了”“真的喜欢它”
#[13]“不喜欢它”“太棒了”“太棒了”
#[16]“太棒了”“我不喜欢”“太棒了”
#[19]“太棒了”“太棒了”“太棒了”
#[22]“太棒了”“太棒了”“太棒了”
#[25]“太棒了”“太棒了”“太棒了”
#[28]“太棒了”“太棒了”“喜欢它”

可能重复：这是我这边的一个错误。输出仍然是NAWell，第一个节点没有标题。如果您将

html\u节点

更改为

html\u节点

，您将获得所有节点，并且您将看到大多数节点都有一个标题。