R 如何从列中分离时间和日期

我有一个数据集。它有一个包含日期和时间的列。我们能把这个分开吗

df
ColA    ColB
A      2020-01-17T03:30:37-05:00
B      2020-01-17T03:30:38-05:00 
C      2020-01-17T03:30:39-05:00

预期产量

df
ColA    ColB                           ColC             ColD             ColE
A      2020-01-17T03:30:37-05:00     2020-01-17     03:30:37            05:00 
B      2020-01-17T03:30:38-05:00     2020-01-17     03:30:38            05:00 
C      2020-01-17T03:30:39-05:00     2020-01-17     03:30:39            05:00 

---

假设

ColB

列是纯文本，您可以尝试只获取子字符串：

df$ColC <- substr(df$ColB, 1, 10)
df$ColD <- substr(df$ColB, 12, 19)
df$ColE <- substr(df$ColB, 21, 25)

df
  ColA                      ColB       ColC     ColD  ColE
1    A 2020-01-17T03:30:37-05:00 2020-01-17 03:30:37 05:00
2    B 2020-01-17T03:30:38-05:00 2020-01-17 03:30:38 05:00
3    C 2020-01-17T03:30:39-05:00 2020-01-17 03:30:39 05:00

---

df$ColC我们可以使用
tidyr:：extract
并使用适当的正则表达式将数据拆分为3列

tidyr::extract(df, ColB, c("ColC", "ColD", "ColE"), regex = "(.*)T(.*)-(.*)", 
               remove = FALSE)

#  ColA                      ColB       ColC     ColD  ColE
#1    A 2020-01-17T03:30:37-05:00 2020-01-17 03:30:37 05:00
#2    B 2020-01-17T03:30:38-05:00 2020-01-17 03:30:38 05:00
#3    C 2020-01-17T03:30:39-05:00 2020-01-17 03:30:39 05:00

数据

df <- structure(list(ColA = structure(1:3, .Label = c("A", "B", "C"
), class = "factor"), ColB = structure(1:3, .Label = c("2020-01-17T03:30:37-05:00", 
"2020-01-17T03:30:38-05:00", "2020-01-17T03:30:39-05:00"), class = "factor")), 
class = "data.frame", row.names = c(NA, -3L))

df
df <- structure(list(ColA = structure(1:3, .Label = c("A", "B", "C"
), class = "factor"), ColB = structure(1:3, .Label = c("2020-01-17T03:30:37-05:00", 
"2020-01-17T03:30:38-05:00", "2020-01-17T03:30:39-05:00"), class = "factor")), 
class = "data.frame", row.names = c(NA, -3L))