如何获取R中分类频率的日时间序列
我有这样一个数据帧:如何获取R中分类频率的日时间序列,r,date,time-series,time-frequency,tidyverse,R,Date,Time Series,Time Frequency,Tidyverse,我有这样一个数据帧: data <- data.frame(daytime = c('2005-05-03 11:45:23', '2005-05-03 11:47:45', '2005-05-03 12:00:32', '2005-05-03 12:25:01', '2006-05-02 10:45:15', '2006-05-02 11:15:14',
data <- data.frame(daytime = c('2005-05-03 11:45:23', '2005-05-03 11:47:45',
'2005-05-03 12:00:32', '2005-05-03 12:25:01',
'2006-05-02 10:45:15', '2006-05-02 11:15:14',
'2006-05-02 11:16:15', '2006-05-02 11:18:03'),
category = c("A", "A", "A", "B", "B", "B", "B", "A"))
print(data)
daytime category date2
1 2005-05-03 11:45:23 A 05/03/05
2 2005-05-03 11:47:45 A 05/03/05
3 2005-05-03 12:00:32 A 05/03/05
4 2005-05-03 12:25:01 B 05/03/05
5 2006-05-02 10:45:15 B 05/02/06
6 2006-05-02 11:15:14 B 05/02/06
7 2006-05-02 11:16:15 B 05/02/06
8 2006-05-02 11:18:03 A 05/02/06
我尝试过:
library(anytime)
data$daytime <- anytime(data$daytime)
data$day <- factor(format(data$daytime, "%D"))
table(data$day, data$category)
A B
05/02/06 1 3
05/03/05 3 1
库(任何时候)
数据:$daydayA使用的解决方案。您的数据中的daily
列的格式很好,因此我们可以直接使用as.Date
,而无需指定其他格式或使用其他函数
library(tidyverse)
data2 <- data %>%
mutate(day = as.Date(daytime)) %>%
count(day, category) %>%
spread(category, n)
data2
# # A tibble: 2 x 3
# day A B
# * <date> <int> <int>
# 1 2005-05-03 3 1
# 2 2006-05-02 1 3
库(tidyverse)
数据2%
突变(日=截止日期(日))%>%
计数(日、类别)%>%
排列(类别,n)
数据2
##tibble:2 x 3
#A天B天
# *
# 1 2005-05-03 3 1
# 2 2006-05-02 1 3
tidyverse的超赞解决方案可能会重复使用
library(tidyverse)
data2 <- data %>%
mutate(day = as.Date(daytime)) %>%
count(day, category) %>%
spread(category, n)
data2
# # A tibble: 2 x 3
# day A B
# * <date> <int> <int>
# 1 2005-05-03 3 1
# 2 2006-05-02 1 3