在R中匹配不同数据帧中的站点
我有多个数据帧,看起来像这样: 专栏中有许多物种,我在这里不作报道。 d1: d2 d3 我想做的是提取每年仅出现在中的sames站点(在R中匹配不同数据帧中的站点,r,dataframe,subset,extract,R,Dataframe,Subset,Extract,我有多个数据帧,看起来像这样: 专栏中有许多物种,我在这里不作报道。 d1: d2 d3 我想做的是提取每年仅出现在中的sames站点(Reef),并将结果输入一个数据框,如下所示: Year Region Reef Depth Transect Pharia pyramidatus 2000 LP ISLOTES 5 1 0.20 2000 LP NORTE 5 1 0.10
Reef
),并将结果输入一个数据框,如下所示:
Year Region Reef Depth Transect Pharia pyramidatus
2000 LP ISLOTES 5 1 0.20
2000 LP NORTE 5 1 0.10
2000 LP NORTE 20 1 0.00
2010 LP ISLOTES 5 1 0.20
2010 LP NORTE 5 1 0.10
2010 LP NORTE 20 1 0.00
2016 LP ISLOTES 5 1 0.20
2016 LP NORTE 20 1 0.00
非常感谢您对
dplyr解决方案的帮助:
library(dplyr)
rbind(df1, df2, df3) %>%
group_by(Reef) %>%
filter(n_distinct(Year) == 3)
结果:
# A tibble: 8 x 6
# Groups: Reef [2]
Year Region Reef Depth Transect Pharia_pyramidatus
<int> <fctr> <fctr> <int> <int> <dbl>
1 2000 LP ISLOTES 5 1 0.2
2 2000 LP NORTE 5 1 0.1
3 2000 LP NORTE 20 1 0.0
4 2010 LP ISLOTES 5 1 0.2
5 2010 LP NORTE 5 1 0.1
6 2010 LP NORTE 20 1 0.0
7 2016 LP ISLOTES 5 1 0.2
8 2016 LP NORTE 20 1 0.0
df1 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2000 LP BALLENA 5 1 0.03
2000 LP ISLOTES 5 1 0.20
2000 LP NORTE 5 1 0.10
2000 LP NORTE 20 1 0.00", header = TRUE)
df2 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2010 LP PLAYA 5 1 0.03
2010 LP ISLOTES 5 1 0.20
2010 LP NORTE 5 1 0.10
2010 LP NORTE 20 1 0.00", header = TRUE)
df3 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2016 LP BALLENA 5 1 0.03
2016 LP ISLOTES 5 1 0.20
2016 LP SUR 5 1 0.10
2016 LP NORTE 20 1 0.00", header = TRUE)
数据:
# A tibble: 8 x 6
# Groups: Reef [2]
Year Region Reef Depth Transect Pharia_pyramidatus
<int> <fctr> <fctr> <int> <int> <dbl>
1 2000 LP ISLOTES 5 1 0.2
2 2000 LP NORTE 5 1 0.1
3 2000 LP NORTE 20 1 0.0
4 2010 LP ISLOTES 5 1 0.2
5 2010 LP NORTE 5 1 0.1
6 2010 LP NORTE 20 1 0.0
7 2016 LP ISLOTES 5 1 0.2
8 2016 LP NORTE 20 1 0.0
df1 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2000 LP BALLENA 5 1 0.03
2000 LP ISLOTES 5 1 0.20
2000 LP NORTE 5 1 0.10
2000 LP NORTE 20 1 0.00", header = TRUE)
df2 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2010 LP PLAYA 5 1 0.03
2010 LP ISLOTES 5 1 0.20
2010 LP NORTE 5 1 0.10
2010 LP NORTE 20 1 0.00", header = TRUE)
df3 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2016 LP BALLENA 5 1 0.03
2016 LP ISLOTES 5 1 0.20
2016 LP SUR 5 1 0.10
2016 LP NORTE 20 1 0.00", header = TRUE)
你所说的“站点”是指礁石Reef
?另外,NORTE
在d3
中不存在,那么你为什么要将其包括在最终df
中?请参阅更新数据的解决方案谢谢你的回复,它解决了问题,我有一个问题,n_distinct(Year)==3如何工作?“这是因为三个数据帧吗?”FabioFavoritto在我的回答中补充了解释。我还添加了一个更通用的版本,以防您不想硬编码数据框中的年数!感谢您的快速和有益的答复!我注意到,在一般情况下,在输出中添加了一个附加列,并带有“Year_distinct”,这不是一个问题,只是如果有人想使用此函数,并且没有发现添加的新列,它应该是一个警告;)@FabioFavoriteTo如果您不想在最终的数据集中显示年份不同
列,您只需添加%%>%select(-Year\u distinct)
:)
rbind(df1, df2, df3) %>%
mutate(Year_distinct = n_distinct(Year)) %>%
group_by(Reef) %>%
filter(n_distinct(Year) == Year_distinct) %>%
select(-Year_distinct)
df1 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2000 LP BALLENA 5 1 0.03
2000 LP ISLOTES 5 1 0.20
2000 LP NORTE 5 1 0.10
2000 LP NORTE 20 1 0.00", header = TRUE)
df2 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2010 LP PLAYA 5 1 0.03
2010 LP ISLOTES 5 1 0.20
2010 LP NORTE 5 1 0.10
2010 LP NORTE 20 1 0.00", header = TRUE)
df3 = read.table(text = "Year Region Reef Depth Transect Pharia_pyramidatus
2016 LP BALLENA 5 1 0.03
2016 LP ISLOTES 5 1 0.20
2016 LP SUR 5 1 0.10
2016 LP NORTE 20 1 0.00", header = TRUE)