R 提取特定单词后的字符串

我试着四处寻找一个类似的问题，但没有找到。我试图在一个特定的单词后立即提取字符串

我有一堆字符串，但我只想提取

“TaskItem:

之后的字符串。我尝试使用

stru extract

，但无法获得所需的输出

以下是一些示例数据：

sample <- structure(c(14L, 10L, 16L, 9L), .Label = c("", "crash: ae01531510acf7b30821ce9d3d28db889e6b1504; manufacture: samsung; cpu: arm64-v8a; opengl: 3; os: Android; orientation: Landscape; nonfatal: false; root: false; online: true; muted: false; background: false; app_version: 1.1.2; ram_current: 2468; ram_total: 3644; disk_current: 4649; disk_total: 4851; bat: 100; run: 1337;", 
"crash: ae01531510acf7b30821ce9d3d28db889e6b1504; manufacture: samsung; cpu: arm64-v8a; opengl: 3; os: Android; orientation: Landscape; nonfatal: false; root: false; online: true; muted: false; background: false; app_version: 1.1.2; ram_current: 2499; ram_total: 3644; disk_current: 4649; disk_total: 4851; bat: 100; run: 221;", 
"crash: ae01531510acf7b30821ce9d3d28db889e6b1504; manufacture: samsung; cpu: arm64-v8a; opengl: 3; os: Android; orientation: Landscape; nonfatal: false; root: false; online: true; muted: true; background: false; app_version: 1.1.2; ram_current: 2559; ram_total: 3644; disk_current: 4649; disk_total: 4851; bat: 100; run: 1215;", 
"crash: ae01531510acf7b30821ce9d3d28db889e6b1504; manufacture: samsung; cpu: arm64-v8a; opengl: 3; os: Android; orientation: Landscape; nonfatal: false; root: false; online: true; muted: true; background: false; app_version: 1.1.2; ram_current: 2627; ram_total: 3644; disk_current: 4649; disk_total: 4851; bat: 100; run: 235;", 
"crash: ae01531510acf7b30821ce9d3d28db889e6b1504; manufacture: samsung; cpu: arm64-v8a; opengl: 3; os: Android; orientation: Landscape; nonfatal: false; root: false; online: true; muted: true; background: false; app_version: 1.1.2; ram_current: 2655; ram_total: 3644; disk_current: 4649; disk_total: 4851; bat: 100; run: 115;", 
"crash: ae01531510acf7b30821ce9d3d28db889e6b1504; manufacture: samsung; cpu: arm64-v8a; opengl: 3; os: Android; orientation: Landscape; nonfatal: false; root: false; online: true; muted: true; background: false; app_version: 1.1.2; ram_current: 2656; ram_total: 3644; disk_current: 4649; disk_total: 4851; bat: 100; run: 1681;", 
"segment: Android; name: CalendarDetailActivity; visit: 1;", 
"segment: Android; name: MainActivity; visit: 1;", "segment: Android; name: OnBoardingActivity; visit: 1;", 
"segment: Android; name: SchedulePreferenceActivity; visit: 1;", 
"segment: Android; name: SplashActivity; start: 1; visit: 1;", 
"segment: Android; name: SplashActivity; visit: 1;", "TaskItem: CURATED_CONTENT;", 
"TaskItem: SCHEDULE_PREFERENCES;", "TaskItem: SCHEDULE;"), class = "factor")

---

sample我们可以将
str\u extract
与regex lookaround一起使用

library(stringr)
str_extract(sample, "(?<=TaskItem:\\s)[^;]+")
#[1] "CURATED_CONTENT" NA                "SCHEDULE"        NA      

库（stringr）
str_extract（sample），（？谢谢！这很有效-我对正则表达式不是很在行，所以我肯定要花几个世纪才能弄清楚！我会在可能的时候接受你的答案！