在R中使用Dplyr转换多列结构
我有一个数据集,df在R中使用Dplyr转换多列结构,r,dplyr,tidyverse,tidyr,R,Dplyr,Tidyverse,Tidyr,我有一个数据集,df State Year 0 1 2 3 4 5 Georgia 2001 10,000 200 300 400 500 800 Georgia 2002 20,000 500 500 1,000 2,000 2,500 Geor
State Year 0 1 2 3 4 5
Georgia 2001 10,000 200 300 400 500 800
Georgia 2002 20,000 500 500 1,000 2,000 2,500
Georgia 2003 2,000 5,000 1,000 400 300 8,000
Washington 2001 1,000 10,000 6,000 8,000 9,900 10,000
Washington 2006 5,000 300 200 900 1,000 8,000
我希望所需的输出如下所示:
State Year Age Population
Georgia 2001 0 10,000
Georgia 2002 0 20,000
Georgia 2003 0 2,000
Georgia 2001 1 200
Georgia 2002 1 500
Georgia 2003 1 5000
Georgia 2001 2 300
Georgia 2002 2 500
Georgia 2003 2 1000
Georgia 2001 3 400
Georgia 2002 3 1000
Georgia 2003 3 400
Georgia 2001 4 500
Georgia 2002 4 2000
Georgia 2003 4 300
Georgia 2001 5 800
Georgia 2002 5 2500
Georgia 2003 5 8000
Washington 2001 0 1000
Washington 2006 0 5000
Washington 2001 1 10000
Washington 2006 1 300
Washington 2001 2 6000
Washington 2006 2 200
Washington 2001 3 8000
Washington 2006 3 900
Washington 2001 4 9900
Washington 2006 4 1000
Washington 2001 5 10000
Washington 2006 5 8200
这是我的dput
structure(list(state = structure(c(1L, 1L, 1L, 2L, 2L), .Label = c("georgia",
"washington"), class = "factor"), year = c(2001L, 2002L, 2003L,
2001L, 2006L), X0 = structure(c(1L, 3L, 4L, 2L, 5L), .Label = c("10,000",
"1000", "20,000", "2000", "5000"), class = "factor"), X1 = structure(c(2L,
4L, 5L, 1L, 3L), .Label = c("10,000", "200", "300", "500", "5000"
), class = "factor"), X2 = c(300L, 500L, 1000L, 6000L, 200L),
X3 = c(400L, 1000L, 400L, 8000L, 900L), X4 = c(500L, 2000L,
300L, 99000L, 1000L), X5 = structure(c(3L, 2L, 4L, 1L, 4L
), .Label = c("10,000", "2500", "800", "8000"), class = "factor")), class = "data.frame", row.names
=
c(NA,
-5L))
这就是我尝试过的:
我知道我必须按州和年份分组,并可能通过使用gather()函数执行某种类型的透视
library(tidyr)
图书馆(dplyr)
df1%分组依据(州,年)%>%
突变(‘年龄’、‘人口’)
我们可以首先通过提取数字部分将列类型转换为数字,然后再进行重塑
library(dplyr)
library(tidyr)
df %>%
mutate_at(vars(matches('\\d+$')), ~readr::parse_number(as.character(.))) %>%
pivot_longer(cols = -c(state, year), names_to = "Age", values_to = "Population")
tidyr::聚集(df,key,value,-c(state,year))
。还请注意,gather
已失效,并由pivot\u longer
替换。
library(dplyr)
library(tidyr)
df %>%
mutate_at(vars(matches('\\d+$')), ~readr::parse_number(as.character(.))) %>%
pivot_longer(cols = -c(state, year), names_to = "Age", values_to = "Population")