在所有列中使用相同因子集的R模型矩阵

在所有列中使用相同因子集的R模型矩阵,r,dummy-data,model.matrix,R,Dummy Data,Model.matrix,我有一组篮球阵容数据,有五列,每列共享相同的因子,如下所示: head(dat) V1 V2 V3 V4 V5 1 MILES,KEATON KINGSLEY,MOSES BELL,ANTHLON HANNAHS,DUSTY DURHAM,JABRIL 2 MILES,KEATON KINGSLEY,MOSES BELL,ANTHLON HANNAHS,DUS

我有一组篮球阵容数据,有五列,每列共享相同的因子,如下所示:

head(dat)
              V1             V2            V3            V4              V5
1   MILES,KEATON KINGSLEY,MOSES  BELL,ANTHLON HANNAHS,DUSTY   DURHAM,JABRIL
2   MILES,KEATON KINGSLEY,MOSES  BELL,ANTHLON HANNAHS,DUSTY   DURHAM,JABRIL
3 KINGSLEY,MOSES   BELL,ANTHLON HANNAHS,DUSTY DURHAM,JABRIL   THOMPSON,TREY
4 KINGSLEY,MOSES   BELL,ANTHLON HANNAHS,DUSTY THOMPSON,TREY     BEARD,ANTON
5  THOMPSON,TREY    BEARD,ANTON KOUASSI,WILLY   WHITT,JIMMY WATKINS,MANUALE
6  THOMPSON,TREY    BEARD,ANTON KOUASSI,WILLY   WHITT,JIMMY WATKINS,MANUALE
我想做的是让每一行都是该行上显示的当前因子的虚拟编码,如下所示:

MILES,KEATON  KINGSLEY,MOSES  BELL,ANTHLON  HANNAHS,DUSTY  DURHAM,JABRIL THOMPSON,TREY  BEARD,ANTON  KOUASSI,WILLY  WHITT,JIMMY  WATKINS,MANUALE
           1               1             1              1              1             0            0               0             0               0
           1               1             1              1              1             0            0               0             0               0
           0               1             1              1              1             1            0               0             0               0
然而,model.matrix似乎只有一列的范围;它不允许我在多个列中共享整个因子集。根据[this thread][1]中的一些建议,我尝试:

df <- as.data.frame(lapply(dat,as.factor))
fList <- lapply(names(df),reformulate,intercept=FALSE)
mList <- lapply(fList,sparse.model.matrix,data=df)
br <- do.call(cBind,mList)
head(br)
6 x 31 sparse Matrix of class "dgCMatrix"
   [[ suppressing 31 column names ‘V1BEARD,ANTON’, ‘V1BELL,ANTHLON’, ‘V1KINGSLEY,MOSES’ ... ]]

1 . . . 1 . . . . 1 . . 1 . . . . . . 1 . . . . . . 1 . . . . .
2 . . . 1 . . . . 1 . . 1 . . . . . . 1 . . . . . . 1 . . . . .
3 . . 1 . . . 1 . . . . . . 1 . . . 1 . . . . . . . . . . . 1 .
4 . . 1 . . . 1 . . . . . . 1 . . . . . . . 1 . . 1 . . . . . .
5 . . . . 1 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . 1
6 . . . . 1 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . 1

df我们可以从
qdapTools

library(qdapTools)
mtabulate(as.data.frame(t(df1)))
# BELL,ANTHLON DURHAM,JABRIL HANNAHS,DUSTY KINGSLEY,MOSES MILES,KEATON THOMPSON,TREY BEARD,ANTON KOUASSI,WILLY
#1            1             1             1              1            1             0           0             0
#2            1             1             1              1            1             0           0             0
#3            1             1             1              1            0             1           0             0
#4            1             0             1              1            0             1           1             0
#5            0             0             0              0            0             1           1             1
#6            0             0             0              0            0             1           1             1
#  WATKINS,MANUALE WHITT,JIMMY
#1               0           0
#2               0           0
#3               0           0
#4               0           0
#5               1           1
#6               1           1

或使用
base R

 table(rep(1:nrow(df1), ncol(df1)), unlist(df1))