如何根据R中另一个变量的频率计算一个变量的百分比
我不确定如何写出来,但我会展示我想要的代码。我试图确定某些人在一项任务中的准确性,这项任务是在多次事件中进行的,然而,有大量的案例如何根据R中另一个变量的频率计算一个变量的百分比,r,frequency,percentage,R,Frequency,Percentage,我不确定如何写出来,但我会展示我想要的代码。我试图确定某些人在一项任务中的准确性,这项任务是在多次事件中进行的,然而,有大量的案例 names <- c("James", "James", "James", "James", "James", "John", "John", "Fred") outcome <- c("
names <- c("James", "James", "James", "James", "James", "John", "John", "Fred")
outcome <- c("successful", "unsuccessful", "unsuccessful", "successful", "successful", "successful",
"unsuccessful", "unsuccessful")
accuracy <- c("60%", "60%", "60%", "60%", "60%", "50%", "50%", "0%")
df <- data.frame(names, outcome, accuracy)
名称使用ave
df$accuracy <- NULL
df <- transform(df, accuracy=ave(outcome %in% "successful", names,
FUN=function(x) paste0(sum(x)/length(x)*100, "%")))
df
# names outcome accuracy
# 1 James successful 60%
# 2 James unsuccessful 60%
# 3 James unsuccessful 60%
# 4 James successful 60%
# 5 James successful 60%
# 6 John successful 50%
# 7 John unsuccessful 50%
# 8 Fred unsuccessful 0%
df$accurity这行吗
> df %>% group_by(names) %>% mutate(accuracy = paste0(100 * sum(outcome == 'successful')/n(),'%'))
# A tibble: 8 x 3
# Groups: names [3]
names outcome accuracy
<chr> <chr> <chr>
1 James successful 60%
2 James unsuccessful 60%
3 James unsuccessful 60%
4 James successful 60%
5 James successful 60%
6 John successful 50%
7 John unsuccessful 50%
8 Fred unsuccessful 0%
>df%>%groupby(name)%>%mutate(准确度=paste0(100*sum(结果='successful')/n(),'%'))
#一个tibble:8x3
#组:名称[3]
命名结果准确性
1成功率60%
2.60%
3.60%
4成功率60%
5.成功率60%
6约翰成功50%
7.50%
8.0%
您能否澄清成功/失败结果的频率是什么意思?以詹姆斯为例,它会是3/5吗?因为它有三个“成功”和两个“失败”?如果是,您是否希望打印成功任务的准确性?