R 如何使用格式化程序

如何使用Formator获得如下输出

data<-data.frame(response=c(48,31,24,29,46,34,25,31,45,37,27,35,37,39,30,38,45,34,29,32,
                             28,17,19,20,32,18,20,22,35,19,22,24,39,16,19,22,31,15,20,22)
                  ,treatment=rep(c("A","B","C","D"),10)
                  ,subject=rep(c("A","B","C","D","E","F","G","H","I","J"),each=4)
                  ,group=rep(c("A","B"),each=20)
                  )

来自任意输入，如

data <- data.frame(response = c(48, 31, 24, 29, 46, 
   34, 25, 31, 45, 37, 27, 35, 37, 39, 30, 38, 45, 
   34, 29, 32, 28, 17, 19, 20, 32, 18, 20, 22, 35, 
   19, 22, 24, 39, 16, 19, 22, 31, 15, 20, 22), treatment = rep(c("A", 
   "B", "C", "D"), 10), subject = rep(c("A", "B", 
   "C", "D", "E", "F", "G", "H", "I", "J"), each = 4), 
   group = rep(c("A", "B"), each = 20))

我想要什么， -以第二个data.frame为例 -执行tidy.sourcefilename，file=filename和 -以类似于第一个data.frame的形式获取data.frame

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如果我可以选择格式化程序忽略这些数据，我也可以。

您使用逗号有点不正常。但是，现在有几个双逗号，我更正了。但请详细说明您的输出应该是什么样子，以及为什么您认为Formator会为您这样做。您好，thx我将主题的内容更改为正确的形式。以防万一有人想尝试一下：注意有点混乱的命名方案：@Klaus使用输出作为输入，并希望输入作为输出。我可以让意思更清楚，我想是吧。Thx用于阅读。