R Kables不是'；看不到我的kable_造型属性？

我试图用

knitr:：kables

吐出两个

不过，我不知道如何让我的风格保持下去。如果我运行一个kable，则样式工作正常：

 kable(
      caption = "Oh look! A Caption",
      starwars %>%
        count(gender, sex) %>%
        arrange(desc(gender)) 
    ) %>%
      kable_styling(bootstrap_options = c("striped", "hover", "condensed"))

给我一张整洁的桌子：

但是如果我试图同时设置两个，格式（或

kable_样式

）就会丢失：

knitr::kables(list(
   kable(caption = "Oh look! A Caption",
         starwars %>%
           count(gender, sex) %>%
           arrange(desc(gender))) %>%
     kable_styling(bootstrap_options = c("striped", "hover", "condensed")),
   
   
   kable(caption = "Oh look! A Caption",
         starwars %>%
           count(gender, sex) %>%
           arrange(desc(gender))) %>%
     kable_styling(bootstrap_options = c("striped", "hover", "condensed"))
 ))

格式设置全部消失：

---

如何将

kable\u样式设置应用于两个
kable
？
非常令人不满意的解决方案是添加第三个
kable\u样式设置（）
调用：

knitr::kables(list(
  kable(caption = "Species",
    starwars %>%
      count(species) %>%
      filter(n > 1)
    ) %>% kable_styling(bootstrap_options = c("striped", "hover", "condensed")),
    kable(caption = "Homeworld",
      starwars %>%
        count(homeworld) %>%
        filter(n > 1)
    ) %>% kable_styling(bootstrap_options = c("striped", "hover", "condensed"))
    
  )
) %>% kable_styling(bootstrap_options = c("striped", "hover", "condensed"))

这看起来很冗长，但它确实有效。
非常令人不满意的解决方案是添加第三个
kable\u styleing（）
调用：

knitr::kables(list(
  kable(caption = "Species",
    starwars %>%
      count(species) %>%
      filter(n > 1)
    ) %>% kable_styling(bootstrap_options = c("striped", "hover", "condensed")),
    kable(caption = "Homeworld",
      starwars %>%
        count(homeworld) %>%
        filter(n > 1)
    ) %>% kable_styling(bootstrap_options = c("striped", "hover", "condensed"))
    
  )
) %>% kable_styling(bootstrap_options = c("striped", "hover", "condensed"))

这似乎很冗长，但它确实有效