R 函数翻译

我尝试将

矩阵

函数参数“翻译”为葡萄牙语，这样做：

portuguese.matrix <- function(dados = NA, nlin = 1, ncol = 1, porlin = FALSE,
                              dimnomes = NULL) {
    matrix(data, nrow, ncol, byrow,
           dimnames)
}

这就是我得到的：

portuguese.matrix(dados = rnorm(9) ,nlin = 3, ncol = 3, dimnomes = list(c("a","b","c"),c("d","e","f")))
Error in as.vector(x, mode) : 
  cannot coerce type 'closure' to vector of type 'any'
Called from: as.vector(data)
Browse[1]> 

R studio将打开一个窗口，显示以下内容：

---

关于如何解决这个问题有什么建议吗？

你在找这样的东西吗

portuguese.matrix <- function(dados = NA, nlin = 1, ncol = 1, porlin = FALSE, dimnomes = NULL) {
  matrix(data = dados,
         nrow = nlin,
         ncol = ncol,
         byrow = porlin,
         dimnames = dimnomes)
 }

 set.seed(123) 
 portuguese.matrix(dados = rnorm(9) ,nlin = 3, ncol = 3, dimnomes =  list(c("a","b","c"),c("d","e","f")))

---

在函数内部，您显示的是

数据

而不是

数据

，以及

nrow

而不是

nlin

。函数的参数应与

矩阵中的输入参数匹配

是否只想通过包装函数使用自己的名称重命名

矩阵

函数签名？在函数内部尝试

矩阵（dados、nlin、ncol、porlin、dimnomes）

。阿卡贝（埃斯佩罗：-）明白了！问题解决了。谢谢

portuguese.matrix <- function(dados = NA, nlin = 1, ncol = 1, porlin = FALSE, dimnomes = NULL) {
  matrix(data = dados,
         nrow = nlin,
         ncol = ncol,
         byrow = porlin,
         dimnames = dimnomes)
 }

 set.seed(123) 
 portuguese.matrix(dados = rnorm(9) ,nlin = 3, ncol = 3, dimnomes =  list(c("a","b","c"),c("d","e","f")))

structure(c(-0.560475646552213, -0.23017748948328, 1.55870831414912, 
0.070508391424576, 0.129287735160946, 1.71506498688328, 0.460916205989202, 
-1.26506123460653, -0.686852851893526), .Dim = c(3L, 3L), .Dimnames = list(
    c("a", "b", "c"), c("d", "e", "f")))