Reactjs 在redux组合减速机中，调用所有减速机是否正确？

我有两个减缩器（计数和搜索），我已经组合。当搜索组件分派时，将调用两个减缩器

这是所有减速器都被调用的预期行为吗

或者，应该只调用最具体的减速器（即搜索）？我必须做什么才能只调用最具体的减速器

以下是搜索、计数和组合减缩器

const initialState = {url:'...'};
function search(state = initialState, action) {
  if (action.type === 'SEARCH') {
    ...
    return state;
  }
  return state;
}
export default search;

搜索组件如下所示

import React, { Component } from 'react';
import { onSearch as onSearchAction } from '../store/actions/Actions.js';
import { connect } from 'react-redux';

class Search extends Component {
  render() {
    return (
      <>
      ....
      </>
    );
  }
}

const mapStateToProps = (state) => {
  return { url: state.url };
}

const mapDispatchToProps = (dispatch, ownProps) => {
  return { onSearch: () => dispatch(onSearchAction()) };
};

const ConnectedSearch = connect(mapStateToProps, mapDispatchToProps)(Search);

export default ConnectedSearch;

这是所有减速器都被调用的预期行为吗

对

我必须做什么才能只调用最具体的减速器

嗯，你可以编写一个自定义的减速机来实现这一点，但我不确定它的好处是什么。大概您会编写这样的代码：“如果是这个动作，或者这个动作，或者这个动作，那么调用reducer 1；否则调用reducer 2”。但是检查动作类型是reducer 1已经在做的事情，所以您只是在复制逻辑。为什么不给两个减速机打电话，让他们处理或忽略他们关心或不关心的事情呢

import CountReducer from './CountReducer.js';
import SearchReducer from './ApiReducer.js';
import { combineReducers } from 'redux'

const reduce = combineReducers({
  count: CountReducer,
  search: SearchReducer
});
export default reduce;

import React, { Component } from 'react';
import { onSearch as onSearchAction } from '../store/actions/Actions.js';
import { connect } from 'react-redux';

class Search extends Component {
  render() {
    return (
      <>
      ....
      </>
    );
  }
}

const mapStateToProps = (state) => {
  return { url: state.url };
}

const mapDispatchToProps = (dispatch, ownProps) => {
  return { onSearch: () => dispatch(onSearchAction()) };
};

const ConnectedSearch = connect(mapStateToProps, mapDispatchToProps)(Search);

export default ConnectedSearch;

export function onSearch() {
  return {
    type: "SEARCH",
    url: '...'
  }
}