Regex 不在引号之间时查找值

使用JavaScript和regex，我希望在每个%20上拆分一个不在引号内的字符串，例如：

Here%20is%20"a%20statement%20"%20for%20Testing%20"%20The%20Values%20"
//easy to read version: Here is "a statement " for Testing " The Values "
                                ______________             ______________

会回来吗

{"Here","is","a statement ","for","Testing"," The Values "}

但我的正则表达式似乎已经不足以构建表达式。谢谢你的帮助

试试看：

var input  = 'Here%20is%20"a%20statement%20"%20for%20Testing%20"%20The%20Values%20"',
    tmp    = input.replace(/%20/g, ' ').split('"'),
    output = []
;

for (var i = 0; i < tmp.length; i++) {
  var part = tmp[i].trim();
  if (!part) continue;

  if (i % 2 == 0) {
    output = output.concat(part.split(' '));
  } else {
    output.push(part);
  }
}

---

一种使用替换方法但不使用替换结果的方法。其思想是在每次出现时使用闭包填充结果变量：

var txt = 'Here%20is%20"a%20statement%20"%20for%20Testing%20"%20The%20Values%20"';
var result = Array();

txt.replace(/%20/g, ' ').replace(/"([^"]+)"|\S+/g, function (m,g1) {
    result.push( (g1==undefined)? m : g1); });

console.log(result);

---

您可以尝试使用以%20作为分隔符的CSV解析器。我认为可以下载用JS编写的CSV解析器。

var txt = 'Here%20is%20"a%20statement%20"%20for%20Testing%20"%20The%20Values%20"';
var result = Array();

txt.replace(/%20/g, ' ').replace(/"([^"]+)"|\S+/g, function (m,g1) {
    result.push( (g1==undefined)? m : g1); });

console.log(result);