Regex 将某个关键字后的单词转换为小写

我正在尝试使用shell脚本将

之后的所有单词转换为

：

SELECT
first_name AS First_Name,
last_name AS Last_Name,
AGE('1990-10-12') AS Person_Age
FROM table1

我需要的输出是

SELECT
first_name AS first_name,
last_name AS last_name,
AGE('1990-10-12') AS person_age
FROM table1

---

如果您使用了GNU sed，则可以使用对的扩展，将其后面的所有内容转换为小写：

$ sed -E 's/(AS)(.*)/\1\L\2/' infile
SELECT
first_name AS first_name,
last_name AS last_name,
AGE('1990-10-12') AS person_age
FROM table1

---

如果您使用了GNU sed，则可以使用对的扩展，将其后面的所有内容转换为小写：

$ sed -E 's/(AS)(.*)/\1\L\2/' infile
SELECT
first_name AS first_name,
last_name AS last_name,
AGE('1990-10-12') AS person_age
FROM table1

使用

awk

awk '/AS/ {for (i=1; i<=NF; i++) if ($i == "AS") $(i+1) = tolower($(i+1))} {print}' < infile.sql

awk'/AS/{for（i=1；i使用
awk

awk '/AS/ {for (i=1; i<=NF; i++) if ($i == "AS") $(i+1) = tolower($(i+1))} {print}' < infile.sql

awk'/AS/{for（i=1；i使用Perl

$ cat aswin.sql
SELECT
first_name AS First_Name,
last_name AS Last_Name,
AGE('1990-10-12') AS Person_Age
FROM table1

$ perl -ne ' { s/\bas\b\s+\b(.+?)\b/AS \L\1\E/gi; print } ' aswin.sql
SELECT
first_name AS first_name,
last_name AS last_name,
AGE('1990-10-12') AS person_age
FROM table1

使用Perl

$ cat aswin.sql
SELECT
first_name AS First_Name,
last_name AS Last_Name,
AGE('1990-10-12') AS Person_Age
FROM table1

$ perl -ne ' { s/\bas\b\s+\b(.+?)\b/AS \L\1\E/gi; print } ' aswin.sql
SELECT
first_name AS first_name,
last_name AS last_name,
AGE('1990-10-12') AS person_age
FROM table1