Ruby on rails 如果关联具有limit子句,则AssociationRelation属性上的Rails sum不正确
我有一种计算统计数据的方法,主要是对模型中的一些浮点属性求和 模型Ruby on rails 如果关联具有limit子句,则AssociationRelation属性上的Rails sum不正确,ruby-on-rails,ruby-on-rails-5,arel,Ruby On Rails,Ruby On Rails 5,Arel,我有一种计算统计数据的方法,主要是对模型中的一些浮点属性求和 模型 class GroupPlayer < ActiveRecord::Base belongs_to :group has_many :scored_rounds has_many :rounds, dependent: :destroy end class Round < ActiveRecord::Base belongs_to :group_player end class ScoredRou
class GroupPlayer < ActiveRecord::Base
belongs_to :group
has_many :scored_rounds
has_many :rounds, dependent: :destroy
end
class Round < ActiveRecord::Base
belongs_to :group_player
end
class ScoredRound < Round
# STI
end
如果玩家没有赢得那场比赛,我在分数榜中总结的4个属性中的3个可能不会被设置为零,因此轮数会被过滤
一切都很顺利,直到我决定增加一个限制使用多少轮。例如,如果我只想要传递给方法_stats的查询中最后25轮的状态,我会调用:
def money_stats(grp,method,limit=100)
sr = self.scored_rounds.where.not(method => nil).order(:date).reverse_order.limit(limit)
method_stats(method,sr,grp)
end
同样,我只是在查询中添加了limit和order子句。所有的记录都很好
如果我在控制台中模拟该过程而不使用上述方法或使用它们!我会得到一个错误的总数
gp = GroupPlayer.find(123)
GroupPlayer Load (2.1ms) SELECT "group_players".* FROM "group_players" WHERE "group_players"."id" = $1 LIMIT $2 [["id", 123], ["LIMIT", 1]]
=> valid group player
sr = gp.scored_rounds.where.not(:quality => nil)
ScoredRound Load (1.7ms) SELECT "rounds".* FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> #<ActiveRecord::AssociationRelation [#<ScoredRound id: 5706, player_id: 123, group_player_id: 123, event_id: 12, type: "ScoredRound", date: "2016-11-04", team: 3, tee: "White", quota: 32, front: 15, back: 15, total: 30, created_at: "2016-11-04 14:18:27", updated_at: "2016-11-04 19:12:47", quality: 0.0, skins: nil, par3: nil, other: nil>,...]
sr.count
(1.5ms) SELECT COUNT(*) FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> 44
sr.sum(:quality)
(1.0ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> 354.166666666667
# Now if I add the order and limit clause
sr = gp.scored_rounds.where.not(:quality => nil).order(:date).reverse_order.limit(25)
ScoredRound Load (1.6ms) SELECT "rounds".* FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) ORDER BY "rounds"."date" DESC LIMIT $2 [["group_player_id", 123], ["LIMIT", 25]]
=> => #<ActiveRecord::AssociationRelation [...]
sr.count
(1.1ms) SELECT COUNT(count_column) FROM (SELECT 1 AS count_column FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) LIMIT $2) subquery_for_count [["group_player_id", 123], ["LIMIT", 25]]
=> 25
sr.sum(:quality)
(1.8ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) LIMIT $2 [["group_player_id", 123], ["LIMIT", 25]]
=> 354.166666666667
### This is the error, it return the sum off all records,
# not the limited???? if I use pluck and sum
sr.pluck(:quality)
=> [10.0, 11.3333333333333, 10.0, 34.0, 0.0, 7.33333333333333, 0.0, 0.0, 31.5, 0.0, 21.3333333333333, 0.0, 19.0, 0.0, 0.0, 7.5, 0.0, 20.0, 10.0, 28.0, 8.0, 9.5, 0.0, 3.0, 24.0]
sr.pluck(:quality).sum
=> 254.49999999999994
我不知道我是在阿雷尔发现了一个漏洞还是我做错了什么。我尝试了一轮,而不是STI得分,结果是一样的
有什么想法吗
# File activerecord/lib/active_record/relation/calculations.rb, line 75
def sum(column_name = nil)
return super() if block_given?
calculate(:sum, column_name)
end
如果调用sr.sum:quality,那么sum将quality作为列名,并计算给定列上的值之和 如果您注意到,无论有无限制,两者的总和结果都是相同的:
sr = gp.scored_rounds.where.not(:quality => nil)
sr.sum(:quality)
(1.0ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> 354.166666666667
sr = gp.scored_rounds.where.not(:quality => nil).order(:date).reverse_order.limit(25)
sr.sum(:quality)
(1.8ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) LIMIT $2 [["group_player_id", 123], ["LIMIT", 25]]
=> 354.166666666667
这是因为LIMIT会影响查询返回的行数,SUM只返回一行,所以该函数将应用于所有44条记录,而不是指定给LIMIT的25条记录。sr.pulk:quality.sum的情况并非如此,它只适用于查询返回的25条记录
我不知道我是在阿雷尔发现了一只虫子还是我做错了什么
遗憾的是,99.9%的时间不是错误,而是我们的错误:谢谢你的解释。事实上,我发现了一篇有一年历史的帖子,它问了同样的问题,并给出了一个解释,说明限制并不是问题的一部分。
sr = gp.scored_rounds.where.not(:quality => nil)
sr.sum(:quality)
(1.0ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> 354.166666666667
sr = gp.scored_rounds.where.not(:quality => nil).order(:date).reverse_order.limit(25)
sr.sum(:quality)
(1.8ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) LIMIT $2 [["group_player_id", 123], ["LIMIT", 25]]
=> 354.166666666667