Ruby on rails 带Rails 5.1表单的嵌套资源
根据,我可以看到一个数组应该通过的model参数传递给Ruby on rails 带Rails 5.1表单的嵌套资源,ruby-on-rails,ruby-on-rails-5.1,Ruby On Rails,Ruby On Rails 5.1,根据,我可以看到一个数组应该通过的model参数传递给form_。但是,当我提供以下内容时: <%= form_with(model: [@trip, @activity], local: true) do |f| %> ... <% end %> rake路由的输出类似于- trip_activities GET /trips/:trip_id/activities(.:format) activities#index
form_。但是,当我提供以下内容时:
<%= form_with(model: [@trip, @activity], local: true) do |f| %>
...
<% end %>
rake路由的输出类似于-
trip_activities GET /trips/:trip_id/activities(.:format) activities#index
POST /trips/:trip_id/activities(.:format) activities#create
new_trip_activity GET /trips/:trip_id/activities/new(.:format) activities#new
edit_trip_activity GET /trips/:trip_id/activities/:id/edit(.:format) activities#edit
trip_activity GET /trips/:trip_id/activities/:id(.:format) activities#show
PATCH /trips/:trip_id/activities/:id(.:format) activities#update
PUT /trips/:trip_id/activities/:id(.:format) activities#update
DELETE /trips/:trip_id/activities/:id(.:format) activities#destroy
trips GET /trips(.:format) trips#index
POST /trips(.:format) trips#create
new_trip GET /trips/new(.:format) trips#new
edit_trip GET /trips/:id/edit(.:format) trips#edit
trip GET /trips/:id(.:format) trips#show
PATCH /trips/:id(.:format) trips#update
PUT /trips/:id(.:format) trips#update
DELETE /trips/:id(.:format) trips#destroy
和我的活动_controller.rb-
before_action :set_activity, only: %i[show update edit destroy]
def edit; end
def update
dates = calculate_datetimes(params[:date_range])
@activity.assign_attributes(name: params[:name],
summary: params[:summary],
start_datetime: dates[0],
end_datetime: dates[1])
if @activity.save
flash[:success] = 'Activity successfully updated'
redirect_to(@trip)
else
set_humanized_daterange
render :edit
end
end
private
def set_activity
@activity = Activity.find(params[:id])
end
tl;dr-我应该如何为嵌套资源设置表单,为什么该表单认为我要使用活动路径
?理想情况下,我希望将此表单移动到一个分部中,并对我的“新建”和“编辑”操作使用相同的表单。您只需将url添加到希望表单指向的路径,即:、url:trip\u activity\u path
或您所点击的路径尝试分别指定模型和url:
form_with(model: @activity, url: [@trip, @activity])
根据文档,url
的值“类似于传递给url\u for或link\u to的值”,因此使用数组应该有效
这也适用于浅嵌套,因为阵列是压缩的。添加到,如果要支持浅嵌套,还可以使用:
form_与(model:[@trip,@activity])
并将edit.html.erb上的渲染更改为将nil传递给trip,如:
并使其通过新的.html.erb中的trip模型更改url很好,但您可以更改模型,该模型允许构建器推断url和任何范围等:
<%= form_with(model: child.new_record? ? [@parent, child] : child, local: true) do |form| %>
新建/编辑视图:
控制器需要从url参数设置@parent,这是嵌套资源的惯例
<%= form_with(model: child.new_record? ? [@parent, child] : child, local: true) do |form| %>