Ruby on rails 在Rails中从不同模型调用数据

我需要能够从不同的模型调用数据——不仅仅是一个字段，而是其中任何一个字段

目前我有以下型号：

kase
person
company
party

我可以通过以下方式将信息从公司呼叫至kase，从个人呼叫至kase：

<li>Client Company Address: <span class="address"><%=h @kase.company.companyaddress %></span></li>
<li>Case Handler: <span><%=h @kase.person.personname %></span></li>

注释的行如下所示：

34: <div id="clientinfo_showhide" style="display:none">
35: <li>Client Company Address: <span class="address"><%=h @kase.company.companyaddress  %></span></li>
36: <li>Client Company Fax: <span><%=h @kase.company.companyfax %></span></li>
37: <li>Case Handler: <span><%=h @kase.person.personname %></span></li>
38: <li>Case Handler Tel: <span><%=h @kase.person.personmobile %></span></li>
39: <li>Case Handler Email: <span><%=h @kase.person.personemail %></span></li>
40: </div>

class Kase
belongs_to :company # foreign key: company_id
belongs_to :person # foreign key in join table

class Person
has_many :kases # foreign key in join table
belongs_to :company

class Company
has_many :kases
has_many :people
def to_s; companyname; end

此人的模型如下所示：

34: <div id="clientinfo_showhide" style="display:none">
35: <li>Client Company Address: <span class="address"><%=h @kase.company.companyaddress  %></span></li>
36: <li>Client Company Fax: <span><%=h @kase.company.companyfax %></span></li>
37: <li>Case Handler: <span><%=h @kase.person.personname %></span></li>
38: <li>Case Handler Tel: <span><%=h @kase.person.personmobile %></span></li>
39: <li>Case Handler Email: <span><%=h @kase.person.personemail %></span></li>
40: </div>

class Kase
belongs_to :company # foreign key: company_id
belongs_to :person # foreign key in join table

class Person
has_many :kases # foreign key in join table
belongs_to :company

class Company
has_many :kases
has_many :people
def to_s; companyname; end

该公司的模式如下：

34: <div id="clientinfo_showhide" style="display:none">
35: <li>Client Company Address: <span class="address"><%=h @kase.company.companyaddress  %></span></li>
36: <li>Client Company Fax: <span><%=h @kase.company.companyfax %></span></li>
37: <li>Case Handler: <span><%=h @kase.person.personname %></span></li>
38: <li>Case Handler Tel: <span><%=h @kase.person.personmobile %></span></li>
39: <li>Case Handler Email: <span><%=h @kase.person.personemail %></span></li>
40: </div>

class Kase
belongs_to :company # foreign key: company_id
belongs_to :person # foreign key in join table

class Person
has_many :kases # foreign key in join table
belongs_to :company

class Company
has_many :kases
has_many :people
def to_s; companyname; end

---

希望这有帮助

您是否在person表中填充了数据

为了写一个正确的答案，问题是他在

kases

表上有

个人id

作为

字符串

他们有错误消息吗？你能给我们看看你的模型和迁移吗？你应该在

kases

表上有

person\u id

。我有，但它是一个字符串，应该是整数吗？