Ruby on rails RubyonRails中REJECT方法的正确使用——帮助我将多行代码转换为RubyOne行代码
我有一系列散列名称和电子邮件,如下所示:Ruby on rails RubyonRails中REJECT方法的正确使用——帮助我将多行代码转换为RubyOne行代码,ruby-on-rails,ruby,arrays,hash,Ruby On Rails,Ruby,Arrays,Hash,我有一系列散列名称和电子邮件,如下所示: array = [{"email"=>"test@test.com", "name"=>"Test"}, {"email"=>"testA@gmail.com", "name"=>"Test A"}, {"name"=>"Test B", "email"=>"testB@test.com"}, {"email"=>"testC@yahoo.com", "name"=>"T
array = [{"email"=>"test@test.com", "name"=>"Test"},
{"email"=>"testA@gmail.com", "name"=>"Test A"},
{"name"=>"Test B", "email"=>"testB@test.com"},
{"email"=>"testC@yahoo.com", "name"=>"Test C"},
{"name"=>"Test D", "email"=>"testD@hotmail.com"},
{"email"=>"testE@test.com"},
{"name"=>"Test F", "email"=>"testF@test.com"}]
我想过滤掉“黑名单”数组中的某些电子邮件。下面的方法很有效,但太冗长了
blacklist = ["@test.com", "@gmail.com"]
na = array
blacklist.each do |b|
na = na.reject{ |e| e["email"].include?(b) }
end
# na => [{"email"=>"testC@yahoo.com", "name"=>"Test C"}, {"name"=>"Test D", "email"=>"testD@hotmail.com"}]
有人能帮我把这个做成性感的红宝石单眼线吗
people.reject { |p| blacklist.include?("@" + p["email"].split("@", 2)[1]) }
请注意,您应该将黑名单
构建为一个集合,以进行包含测试O(1)
如果这个散列来自数据库,那么您应该在数据库端进行过滤 如果不是,则不要为每个黑名单项目运行单独的
拒绝
。你可能想要像这样的东西
array.reject {|rec| blacklist.include? "@#{rec['email'].split('@').last}" }
还有一个建议:)
酷。我不熟悉设置的
。很有趣,谢谢大家。这三种解决方案都奏效了。我运行了5000次迭代并平均了它们的速度(例如,运行时)。它们都相当接近(最多相差1e-05秒),但@WarHog的解决方案似乎是平均最快的(1.41e-05)。它也是一个需要对我现有代码进行最少修改的代码。你可以这样做,但为什么要添加额外的块呢?喜欢它,但在这种特殊情况下,我更喜欢“.include?b”,而不是“.include?b”,因为这就是它的意图。
array.reject {|rec| blacklist.include? "@#{rec['email'].split('@').last}" }
array.reject { |h| blacklist.any? { |b| h["email"].include? b } }
array = [{"email"=>"test@test.com", "name"=>"Test"},
{"email"=>"testA@gmail.com", "name"=>"Test A"},
{"name"=>"Test B", "email"=>"testB@test.com"},
{"email"=>"testC@yahoo.com", "name"=>"Test C"},
{"name"=>"Test D", "email"=>"testD@hotmail.com"},
{"email"=>"testE@test.com"},
{"name"=>"Test F", "email"=>"testF@test.com"}]
blacklist = ["test.com", "gmail.com"]
na = array.reject { |e| blacklist.include?(e["email"].split('@').last) }
=> [{"name"=>"Test C", "email"=>"testC@yahoo.com"}, {"name"=>"Test D", "email"=>"testD@hotmail.com"}]