Ruby 如何使用引发的错误呈现正确的JSON格式

我确信我这里有一个基本的

rescue\u问题，但是，当我的
验证失败时出现异常时，我试图获得所需的输出，但我似乎无法找到它

当前我的
ApplicationController
如下所示：

class ApplicationController < ActionController::API
  include ActionController::Serialization

  rescue_from ActiveRecord::RecordInvalid do |e|
  render json: {error: e.message}, status: 404
  end  

end

    {
  "organization_id": [
    "can't be blank"
  ],
  "description": [
    "can't be blank"
  ],
  "artwork": [
    "can't be blank"
  ],
  "language_code": [
    "can't be blank"
  ],
  "copyright": [
    "can't be blank"
  ],
  "right_to_left": [
    "is not included in the list"
  ],
  "digital_audio": [
    "is not included in the list"
  ],
  "portion": [
    "is not included in the list"
  ],
  "electronic_text": [
    "is not included in the list"
  ],
  "old": [
    "is not included in the list"
  ],
  "new": [
    "is not included in the list"
  ]
}

我想要得到的输出（或类似的输出）如下所示：

class ApplicationController < ActionController::API
  include ActionController::Serialization

  rescue_from ActiveRecord::RecordInvalid do |e|
  render json: {error: e.message}, status: 404
  end  

end

    {
  "organization_id": [
    "can't be blank"
  ],
  "description": [
    "can't be blank"
  ],
  "artwork": [
    "can't be blank"
  ],
  "language_code": [
    "can't be blank"
  ],
  "copyright": [
    "can't be blank"
  ],
  "right_to_left": [
    "is not included in the list"
  ],
  "digital_audio": [
    "is not included in the list"
  ],
  "portion": [
    "is not included in the list"
  ],
  "electronic_text": [
    "is not included in the list"
  ],
  "old": [
    "is not included in the list"
  ],
  "new": [
    "is not included in the list"
  ]
}

我不知道怎样才能得到这个。当我在
ApplicationController
中注释掉
rescue\u from
方法并设置my
RecordController
创建方法时，我得到了所需的输出，如下所示：

  def create
    r = Record.create(record_params)
    r.save
    if r.save
    render json: r
    else
      render json: r.errors
    end
  end

虽然这是我想要的，我必须去每一个控制器，并添加这个，但这不是一个干燥的方法。。。我宁愿将其集中在
ApplicationController

感谢您的帮助。
谢谢

我已经检查了&
您可以这样做：

def create
  r = Record.create(record_params)
  if r.save
    render json: r.to_json
  else
    render json: errors: r.errors, status: 422
  end
end

如果返回and error，它将返回以下内容：

{
  errors:
    {
      attr_1:["can't be blank"],
      attr_2:["can't be blank"]
    }
}

与您展示的第一个示例相关，ruby的Exception消息以您描述的方式返回错误。我通常看到
rescue\u from
被用来返回通用404页面

希望这能有所帮助
经过更多的研究，我找到了答案

异常对象
e
在主体的rescue\u中有一个
记录
属性和导致异常的记录，您可以使用该记录的
错误
属性来提取错误，并以您想要的格式创建响应：

我在
ApplicationController
中将这一行编辑为：

rescue_from ActiveRecord::RecordInvalid do |e|
  render json: {error: {RecordInvalid: e.record.errors}}, status: 406
end

将RecordController的创建方法更改为：

def create
    r = Record.create!(record_params)
    render json: r
end

这将给出输出：

 {
  "error": {
    "RecordInvalid": {
      "organization_id": [
        "can't be blank"
      ],
      "name": [
        "can't be blank"
      ],
      "description": [
        "can't be blank"
      ],
      "artwork": [
        "can't be blank"
      ],
      "language_code": [
        "can't be blank"
      ],
      "copyright": [
        "can't be blank"
      ],
      "right_to_left": [
        "is not included in the list"
      ],
      "digital_audio": [
        "is not included in the list"
      ],
      "portion": [
        "is not included in the list"
      ],
      "electronic_text": [
        "is not included in the list"
      ],
      "old": [
        "is not included in the list"
      ],
      "new": [
        "is not included in the list"
      ]
    }
  }
}

如果引发了其他异常，并且希望呈现示例，这将非常有帮助：

rescue_from ActiveRecord::RecordNotFound do
  render json: {error: {RecordNotFound: "Record not found for id: #{params[:id]}. Maybe deleted?"}}, status: 404    
end 

使用此选项，如果我搜索无效记录
44
，它将呈现：

{
 "error": {
    "RecordNotFound": "Record not found for id: 44. Maybe deleted?"
  }
}

我希望这个答案能帮助别人！干杯
只是更新，接受的答案不是错误说明

查看上面链接的规范，因为有几个不同的键可以随错误对象一起返回

{
 "error": {
    "title": "RecordNotFound",
    "detail": "Record not found for id: 44. Maybe deleted?"
  }
}

我正试图避免自己必须向每个控制器和操作添加代码。用你的方法，我必须这样做。这就是我只想将代码添加到
ApplicationController
的原因。是的，在不尝试解析异常消息的情况下，我不确定如何获得与对象本身返回的格式相同的格式。