Ruby groupby散列数组转换为数组散列数组？

我正在尝试用ruby进行数据操作

给定这个散列数组

peepz = [
{
  :name => 'ted',
  :phone => '555-1234',
  :color => 'red'
},
{
  :name => 'bill',
  :phone => '555-2222',
  :color => 'green'
},
{
  :name => 'ted',
  :phone => '555-3333',
  :color => 'orange'
},
{
  :name => 'dan',
  :phone => '555-7777',
  :color => 'violet'
},
{
  :name => 'ted',
  :phone => '555-4444',
  :color => 'yellow'
},
{
  :name => 'dan',
  :phone => '555-6666',
  :color => 'orange'
}
];

我想要这个输出

peepz2 = [
  {
    :name => 'ted'
    :phone => ['555-1212','555-3333','555-4444']
    :color => ['red','orange','yellow']
  },
  {
    :name => 'bill'
    :phone => ['555-2222']
    :color => ['green']
  },
  {
    :name => 'dan'
    :phone => ['555-7777','555-6666']
    :color => ['violet','orange']
  },
]

这是我到目前为止所拥有的

def groupbyer ( peepz, *fields )
    peepz.groupby do |peep|
      key = ''
      fields.each do |field|
        key += peep[field].to_s
      end
    end.each do |group|
      ????
    end
end

groupbyer(peepz, :name)

这种方法必须推广。它不能硬编码peepz的字段

---

用ruby完成这个任务的好方法是什么？

另一种方法使用aka merge的形式！使用块确定合并的两个哈希中存在的键的值：

peepz
.group_by{|h| h[:name]}.values
.map{|a| a.inject{|h1, h2| h1.merge(h2){|k, v1, v2| k == :name ? v1 : [*v1, v2]}}}

代码

范例

对于问题中给出的peepz：

peep_merge(peepz)
  #=> [{:name=>"ted",                   
  #     :phone=>["555-1234", "555-3333", "555-4444"],
  #     :color=>["red", "orange", "yellow"]},
  #    {:name=>"bill",
  #     :phone=>["555-2222"],
  #     :color=>["green"]},
  #    {:name=>"dan",
  #     :phone=>["555-7777", "555-6666"],
  #     :color=>["violet", "orange"]}]

解释

最后，要更正：name键的值：

---

提供上面示例中显示的结果。

另一种方法使用aka merge的形式！使用块确定合并的两个哈希中存在的键的值：

代码

范例

对于问题中给出的peepz：

peep_merge(peepz)
  #=> [{:name=>"ted",                   
  #     :phone=>["555-1234", "555-3333", "555-4444"],
  #     :color=>["red", "orange", "yellow"]},
  #    {:name=>"bill",
  #     :phone=>["555-2222"],
  #     :color=>["green"]},
  #    {:name=>"dan",
  #     :phone=>["555-7777", "555-6666"],
  #     :color=>["violet", "orange"]}]

解释

最后，要更正：name键的值：

提供上面示例中显示的结果

a = peepz.each_with_object({}) { |g,h|
      h.update(g[:name]=>(g.merge(g) { |*_,v|
        [v] })) { |_,oh,nh| oh.merge(nh) { |_,ov,nv| ov+nv } } }
  #=> {"ted" =>{:name=>["ted", "ted", "ted"],
  #             :phone=>["555-1234", "555-3333", "555-4444"],
  #             :color=>["red", "orange", "yellow"]},
  #    "bill"=>{:name=>["bill"],
  #             :phone=>["555-2222"],
  #             :color=>["green"]},
  #    "dan" =>{:name=>["dan", "dan"], 
  #             :phone=>["555-7777", "555-6666"],
  #             :color=>["violet", "orange"]}} 
b = a.values
  #=>         [{:name =>["ted", "ted", "ted"],
  #             :phone=>["555-1234", "555-3333", "555-4444"],
  #             :color=>["red", "orange", "yellow"]},
  #            {:name =>["bill"],
  #             :phone=>["555-2222"],
  #             :color=>["green"]},
  #            {:name =>["dan", "dan"],
  #             :phone=>["555-7777", "555-6666"],
  #             :color=>["violet", "orange"]}]

b.each { |h| h[:name] = h[:name].first }