Ruby等待来自外部进程的信号

有没有办法让Ruby进程/线程暂停自己，直到它被来自某个外部进程的信号（或其他进程间通信机制）恢复？我尝试了以下方法，但线程似乎没有被唤醒：

this_thread = Thread.current
Thread.new do
  Signal.trap("INT") do
    puts "\nWaking up!"
    this_thread.run
  end
  sleep
end

puts "Going to sleep..."
Thread.stop
puts "Now awake! =)"

运行示例：

$ ruby wake_on_signal.rb Going to sleep... ^C Waking up! ^C Waking up! ^C Waking up! $ ruby sleep_until_signal.rb Going to sleep... ^C Waking up! Now awake! =) $ ruby wake_on_signal.rb Going to sleep... ^C Waking up! Now awake! =) 运行示例：

$ ruby wake_on_signal.rb Going to sleep... ^C Waking up! ^C Waking up! ^C Waking up! $ ruby sleep_until_signal.rb Going to sleep... ^C Waking up! Now awake! =) $ ruby wake_on_signal.rb Going to sleep... ^C Waking up! Now awake! =) $ruby sleep\u until\u signal.rb 要睡觉了。。。 ^C 醒醒！ 现在醒来！=）

---

您可以使用退出时的

来执行此操作：

at_exit do
  puts "Now awake! =)"
end

Signal.trap("INT") do
  puts "\nWaking up!"
  exit
end

puts "Going to sleep..."
sleep

运行示例：

$ ruby wake_on_signal.rb 
Going to sleep...
^C
Waking up!
^C
Waking up!
^C
Waking up!
$ ruby sleep_until_signal.rb 
Going to sleep...
^C
Waking up!
Now awake! =)
$ ruby wake_on_signal.rb 
Going to sleep...
^C
Waking up!
Now awake! =)
$ruby wake_on_signal.rb
要睡觉了。。。
^C
醒醒！
现在醒来！=）
这大约晚了三年，但可能对未来的读者有所帮助：

puts "kill -#{Signal.list["USR1"]} #{Process.pid}"
thr = Thread.new do
    this_thread = Thread.current
  Signal.trap("USR1") do
    puts "\nWaking up!"
    this_thread.kill
  end
  sleep
end

puts "Going to sleep..."
thr.join
puts "Now awake! =)"

这将暂停主线程并等待USR1信号。它打印出可以用来唤醒线程的命令。在我的系统上，这个打印

$ ruby signal_handler.rb
kill -30 66771  
Going to sleep...

Waking up!
Now awake! =)

哈哈。很好的尝试，但我真的需要程序在唤醒后继续运行P在收到信号后，我的真实程序需要做的事情远不止打印“Now awake！=）”然后退出。你可以把所有这些都放到一个方法中，然后在退出时调用它但是我明白你的意思了——能够停下来并重新开始几次会很好。