Ruby 列添加

我尝试根据日期和时间在列中求和（值介于“，”）之间）

例如：

RG Data,2015/02/27,18:02:07,"0","52",50.0,5.3,44.7,5.6,100.0,0.23,0.03,0.20,6.3,4.5
RG Data,2015/02/27,18:02:07,"1","52",36.9,22.3,14.6,39.9,100.0,0.59,0.16,0.43,7.5,29.9
RG Data,2015/02/27,18:03:06,"0","52",21.2,0.7,20.5,50.0,100.0,0.08,0.00,0.08,0.0,4.2
RG Data,2015/02/27,18:03:06,"1","52",245.6,233.4,12.2,73.7,100.0,2.08,1.83,0.25,8.0,21.4
... more lines after...

输出：

RG Data,2015/02/27,18:02:07,86.9,27.6,59.3,....
RG Data,2015/02/27,18:03:06,266.8,234.1,....

其中：86.9来自：“50.0”（第1行）+36.9（第2行）。等对于每列

带awk的代码：

for TIME in $(awk -F ',|/' '{print $4","$5}' FILE | sort -u) ;do  echo -n "$TIME; awk -F ',' "/$TIME/ {SUM += \$6} END { print SUM}" FILE ; done

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非常感谢您的帮助

此awk one liner可产生接近所需输出的效果：

$ awk -F, '{k=$1FS$2FS$3;seen[k];for(i=6;i<=NF;++i)sum[k,i]+=$i}END{for(i in seen){printf "%s,",i;for(j=6;j<=NF;++j)printf "%s%s",sum[i ,j],(j<NF?FS:RS)}}' file
RG Data,2015/02/27,18:03:06,266.8,234.1,32.7,123.7,200,2.16,1.83,0.33,8,25.6
RG Data,2015/02/27,18:02:07,86.9,27.6,59.3,45.5,200,0.82,0.19,0.63,13.8,34.4

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$awk-F'{k=$1FS$2FS$3；参见[k]；用于（i=6；i你的问题是什么？我无法理解你的第一句话。对不起，我忘了……谢谢你的回答，汤姆，很好的awk命令……但事实上，后面有几行时间不同。我编辑了我的帖子。请看我修改过的脚本。非常感谢你，汤姆，你的awk命令工作得很好！！：）