ruby套接字dgram示例
我试图在ruby中使用unix套接字和SOCK_DGRAM,但我很难弄清楚如何使用。到目前为止,我一直在尝试这样的事情:ruby套接字dgram示例,ruby,sockets,unix-socket,Ruby,Sockets,Unix Socket,我试图在ruby中使用unix套接字和SOCK_DGRAM,但我很难弄清楚如何使用。到目前为止,我一直在尝试这样的事情: sock_path = 'test.socket' s1 = Socket.new(Socket::AF_UNIX, Socket::SOCK_DGRAM, 0) s1.bind(Socket.pack_sockaddr_un(sock_path)) s2 = Socket.new(Socket::AF_UNIX, Socket::SOCK_DGRAM, 0) s2.bin
sock_path = 'test.socket'
s1 = Socket.new(Socket::AF_UNIX, Socket::SOCK_DGRAM, 0)
s1.bind(Socket.pack_sockaddr_un(sock_path))
s2 = Socket.new(Socket::AF_UNIX, Socket::SOCK_DGRAM, 0)
s2.bind(Socket.pack_sockaddr_un(sock_path))
s1.send("HELLO")
s2.recv(5) # should equal "HELLO"
有人有这方面的经验吗?在常见情况下,客户端和服务器套接字都需要使用
connect
和bind
,因此需要两个不同的地址进行绑定
require 'socket'
sock_path = 'test.socket'
sock_path2 = 'test2.socket'
s1 = Socket.new(Socket::AF_UNIX, Socket::SOCK_DGRAM, 0)
s1.bind(Socket.pack_sockaddr_un(sock_path))
s2 = Socket.new(Socket::AF_UNIX, Socket::SOCK_DGRAM, 0)
s2.bind(Socket.pack_sockaddr_un(sock_path2))
s2.connect(Socket.pack_sockaddr_un(sock_path))
s1.connect(Socket.pack_sockaddr_un(sock_path2))
s1.send("HELLO", 0)
puts s2.recv(5)
=> HELLO