Ruby 使用哈希处理文件

下面是我想要存储到哈希表中的输入文件，对其进行排序，并以如下所示的格式输出

输入文件

Name=Ashok, Email=ashok85@gmail.com, Country=India, Comments=9898984512
Email=raju@hotmail.com, Country=Sri Lanka, Name=Raju
Country=India, Comments=45535878, Email=vijay@gmail.com, Name=Vijay
Name=Ashok, Country=India, Email=ashok37@live.com, Comments=8898788987

输出文件（按名称排序）

---

到目前为止，我已经从文件中读取了数据，并将每一行存储到一个数组中，但我仍然停留在hash[key]=>value上

file_data = {} 
File.open('input.txt', 'r') do |file| 
  file.each_line do |line| 
     line_data = line.split('=') 
     file_data[line_data[0]] = line_data[1]
   end 
end 
puts file_data

---

假设输入文件中的每一行都有由逗号分隔的

key=value

字符串模式，则需要先围绕逗号拆分该行，然后围绕等号拆分该行。以下是已更正代码的版本：

# Need to collect parsed data from each line into an array
array_of_file_data = []

File.open('input.txt', 'r') do |file| 

  file.each_line do |line| 

     #create a hash to collect data from each line
     file_data = {} 

     # First split by comma
     pairs = line.chomp.split(", ")

     pairs.each do |p|
        #Split by = to separate out key and value
        key_value = p.split('=') 
        file_data[key_value[0]] = key_value[1]  
     end

     array_of_file_data << file_data
   end 
end 
puts array_of_file_data

---

下面给出了程序的更完整版本

hash_array = []

# Parse the lines and store it in hash array
File.open("sample.txt", "r") do |f|
    f.each_line do |line|
       # Splits are done around , and = preceded or followed 
       # by any number of white spaces
       splits = line.chomp.split(/\s*,\s*/).map{|p| p.split(/\s*=\s*/)}

       # to_h can be used to convert an array with even number of elements
       # into a hash, by treating it as an array of key-value pairs
       hash_array << splits.to_h 
    end
end

# Sort the array of hashes
hash_array = hash_array.sort {|i, j| i["Name"] <=> j["Name"]}

# Print the output, more tricks needed to get it better formatted
header = ["Name", "Email", "Country", "Comments"]
puts header.join(" ")
hash_array.each do |h|
    puts h.values_at(*header).join(" ")
end

---

您可能想参考一下更具格式的表格输出

我试过了，但没有告诉您免费做作业。我从文件中读取数据并将每一行存储到数组中，但是我被困在hash[key]=>valuefile\u data={}file.open（'input.txt'，'r'）do | file | file.each|line do | line | line | line | data=line.split（'='）file\u data[line\u data[0]]=line\u data[1]结束文件_data@anjalirai下一次，请分享您的代码，以便其他人可以进一步指导。我已将您的代码添加到您的问题中。如果需要，请随时编辑您的问题以添加更多详细信息。希望这些电子邮件（和潜在的手机号码）在您的控制之下……在互联网上这样发布是非常危险的。谢谢。。下次我将分享正确的代码排序部分有一个错误，现在修复。

{"Name"=>"Ashok", "Email"=>"ashok85@gmail.com", "Country"=>"India", "Comments"=>"9898984512"}
{"Email"=>"raju@hotmail.com", "Country"=>"Sri Lanka", "Name"=>"Raju"}
{"Country"=>"India", "Comments"=>"45535878", "Email"=>"vijay@gmail.com", "Name"=>"Vijay"}
{"Name"=>"Ashok", "Country"=>"India", "Email"=>"ashok37@live.com", "Comments"=>"8898788987"}

hash_array = []

# Parse the lines and store it in hash array
File.open("sample.txt", "r") do |f|
    f.each_line do |line|
       # Splits are done around , and = preceded or followed 
       # by any number of white spaces
       splits = line.chomp.split(/\s*,\s*/).map{|p| p.split(/\s*=\s*/)}

       # to_h can be used to convert an array with even number of elements
       # into a hash, by treating it as an array of key-value pairs
       hash_array << splits.to_h 
    end
end

# Sort the array of hashes
hash_array = hash_array.sort {|i, j| i["Name"] <=> j["Name"]}

# Print the output, more tricks needed to get it better formatted
header = ["Name", "Email", "Country", "Comments"]
puts header.join(" ")
hash_array.each do |h|
    puts h.values_at(*header).join(" ")
end

Name Email Country Comments
Ashok ashok85@gmail.com India 9898984512
Ashok ashok37@live.com India 8898788987
Raju raju@hotmail.com Sri Lanka 
Vijay vijay@gmail.com India 45535878